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Leto [7]
2 years ago
10

The ratio of losses to wins for Kyle's team is 3 to 2. If the team had played the same number of games, but had won twice as man

y of its games, what would the ratio of losses to wins have been? Express your answer as a common fraction.
Mathematics
2 answers:
Fiesta28 [93]2 years ago
4 0

Answer: The new ratio will be 1/4

Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.

So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.

So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4

natali 33 [55]2 years ago
3 0

Answer: the ratio would ben 1 to 4, or (1/4) as a common fraction, this means that the number of games that the team lost is equal to 1/4 of the games that the team won.

Step-by-step explanation:

the ratio is 3 to 2

this means that if they played 5 games (because 3 + 2 = 5), 3 of those games were losses and 2 where wins.

Now, if they played the same number of games (5) and won twice as many of the games (2) them would have wined 2*2 = 4 of 5 games.

then the rate of loses to wins is:

1 to 4

this means that they lost 1 game for every 4 wins.

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A repairman charges $18 per hour to repair appliances plus $0.27 per mile to drive to the house and back. It took the repairman
ivolga24 [154]

Answer: The charge was right.

Step-by-step explanation:

If he charged $18 per hour, it means he charged $18 for 60 minutes. He worked for 2 hours 15 minutes which is (60 ×2) + 15 = 135 minutes. For 135 mins, (135 ×18)÷ 60 = 40.5.

He drove 21 miles to his house and 21 miles back. That is 21×2= 42. And for $0.27 = $11.34.

Adding the costs, 40.5 + 11.34 = $51.84

5 0
2 years ago
A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids
NemiM [27]

Answer:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35

Now we can find the sampel deviation with this formula:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

6 0
2 years ago
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Which shows the correct solution of the equation<br> 1/2 a + 2/3b = 50 when b=30
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1/2a + 2/3(30)= 50
1/2a + 20 = 50
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A= 30(2)
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The solution is 60.

Hope this helps!
4 0
2 years ago
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a group of 10 people ran an average of 2.7 miles in one week. if the first 4 people in the group averaged 3 miles, what did the
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In this question, 10 people average running distance is 2.7miles. Then the sum of their running distance would be: 10 people * 2.7 miles/people= 27 miles.

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total distance = group1 * average1 + group2 * average2
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average2= 15 miles/6people= 2.5 miles/people
4 0
2 years ago
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