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eduard
2 years ago
9

Insert the greater than, less than, or equal sign (>, <, or =) to make each statement true.

Mathematics
1 answer:
photoshop1234 [79]2 years ago
6 0

For this case we have:

Option A:

\frac {45} {45} = 1

So:

1 = 1\\\frac {45} {45} = 1

Option B:

\frac {6} {3} = 2

So:

1

Option C:

\frac {2} {7} = 0.29

So:

0.29

Option D:

\frac {64} {23} = 2.78\\2.78> 1\\\frac {64} {23}> 1

Answer:

\frac {45} {45} = 1\\1

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5 0
2 years ago
1.5r-3r+8r+2.5r=<br> please show me what the equation is in simplest form thanks
sladkih [1.3K]

Answer:

12.5r

Step-by-step explanation:

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2 years ago
The number of acres in a region cleared for farming follows the formula a = f (t) = 2t2 where t is the number of months since th
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we are given

a=f(t)=2t^2

we can use average rate of change formula from t=a to t=b

A=\frac{f(b)-f(a)}{b-a}

Here, we are given from t=1 to t=4

so, we will get formula as

A=\frac{f(4)-f(1)}{4-1}

now, we can plug values

A=\frac{2(4)^2-2(1)^2}{4-1}

now, we can simplify it

A=10

the average rate of change in the number of acres cleared for farming between t = 1 and t = 4  is 10 acres/ month.............Answer

6 0
2 years ago
Which pair of expressions has equivalent values? 1 Superscript 13 and 1 Superscript 15 6 Superscript 1 and 9 Superscript 1 7 Sup
lora16 [44]

Answer:

1 Superscript 13 and 1 Superscript 15

Step-by-step explanation:

The process of exponentiation can be mathematically written as:

a^b

where a is called the base, and b is called the exponent.

Basically it means that we have to multiply the base with itself as many times as the value of the exponent.

For example 2^4 is 2•2•2•2

Having this in mind, 1^13 and 1^15 have equivalent values, because no matter how many times we multiply 1 with itself it will always be equal to 1.

8 0
2 years ago
Read 2 more answers
The Ignorance Survey: United Kingdom A survey was conducted in the United Kingdom, where respondents were asked if they had a un
lukranit [14]

Answer:

Here we have given two catogaries as degree holder and non degree holder.

So here we have to test the hypothesis that,

H0 : p1 = p2 Vs H1 : p1 not= p2

where p1 is population proportion of degree holder.

p2 is population proportion of non degree holder.

Assume alpha = level of significance = 5% = 0.05

The test is two tailed.

Here test statistic follows standard normal distribution.

The test statistic is,

Z = (p1^ - p2^) / SE

where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]

p1^ = x1/n1

p2^ = x2/n2

p^ = (x1+x2) / (n1+n2)

This we can done in TI_83 calculator.

steps :

STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER

Test statistic Z = 1.60

P-value = 0.1090

P-value > alpha

Fail to reject H0 or accept H0 at 5% level of significance.

Conclusion : There is not sufficient evidence to say that  the percent of correct answers is significantly different between degree holders and non-degree holders.

7 0
2 years ago
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