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s2008m [1.1K]
2 years ago
9

the area of a rectangle is 54x^9y^8 square yards if the length of the rectangle is 6x^3y^4 yards what expression represents the

width of the rectangle in yards
Mathematics
2 answers:
user100 [1]2 years ago
8 0

We are given rectangle

Area=54x^9y^8

so, we have

A=54x^9y^8

length=6x^3y^4

so, we have

L=6x^3y^4

Let's assume

width of the rectangle in yards as W

we know that

A=L*W

now, we can plug values

54x^9y^8=(6x^3y^4)*W

now, we can solve for W

W=\frac{54x^9y^8}{6x^3y^4}

W=9x^6y^4

so, width of rectangle is 9x^6y^4............Answer


valentinak56 [21]2 years ago
6 0
I think your answer will be 48x^6y^4
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Dev has 9 shells. Zoe has 55 shells, Zoe gives some shells to Dev. Now zoe has 3 times as many shells as dev. How many shells do
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Answer:

number of shells zoe gives to dev  = 7

number of shells zoe is left with  = 55-7= 48

number of shells dev has = 9+7=16

Step-by-step explanation:

let the initial number of shells that dev has be A, and initial number of shells that zoe has be B.

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If ray NP bisects &lt;MNQ, m&lt;MNQ=(8x+12)°, m&lt;PNQ=78°, and m&lt;RNM=(3y-9)°, find the value of x and y
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Step 1

<u>Find the measure of angle x</u>

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m<PNQ=78°

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Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage ea
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Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

 

The standard error of the proportion is:

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The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068

Then, the lower and upper bounds of the confidence interval are:

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The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

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