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Rama09 [41]
2 years ago
12

A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. find the value that is +3 standard devi

ations away from the mean. 48.0 78.9 20.1 69.9
Mathematics
2 answers:
lidiya [134]2 years ago
3 0
69.9 is exactly 3 standard deviations away, which means that 78.9 is +3 (more than 3) standard deviations

So the answer is 78.9
Simora [160]2 years ago
3 0

Answer:

D. 69.9

Step-by-step explanation:

We have been given that a set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. We are asked to find the value that is +3 standard deviations away from the mean.

To find the value that is 3 standard deviation away from mean, we will multiply 3 by standard deviation and ad the result to mean.

45+(3\times 8.3)

45+24.9

69.9

Therefore, 69.9 is 3 standard deviation away from mean of or given data set and option D is the correct choice.

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In 2001, a total of 15,555 homicide deaths occurred among males and 4,753 homicide deaths occurred among females. The estimated
deff fn [24]

Answer:

a. 11

b. 3

c. homicide mortality rate

d. 11:3

Step-by-step explanation:

a.) If 15,555 homicide cases were recorded among males of 139,813,000 population, then in every 100,000 males, the number of homicides cases will become:

= [15,555/139,813,000] * 100,000

= 11.13 aproximately 11 homicide cases in every 100,000 males.

b.) If 4,753 homicide cases were recorded among Females of 144,984,000 population, then in every 100,000 Females, the number of homicides cases will become:

= [4753/144,984,000] * 100,000

= 3.28 approximately 3 homicide cases in every 100,000 females

C.) Homicide-mortality rate

d.) ratio of male to female homicide rate = 11 : 3

e.) What those rates means is that in every 100,000

Males in 2001, 11 of them were Victims of homicide and in every 100,000 females, 3 of them are victims of homicide.

6 0
2 years ago
Which logic statement represents this argument? If it’s a weekend, I exercise. It’s not a weekend. So, I won’t exercise. Assume
geniusboy [140]
P = It is a weekend
Q = I will exercise

If "It is a weekend", then "I will exercise"
But "It is NOT a weekend"
Therefore, "I will NOT exercise"

Using P and Q our statement would look like this,
If P, then Q
But not P
Therefore not Q

Or symbolically like this:
P -> Q
~P
\therefore ~Q

I'm sorry that this doesn't match up with the options you posted.
Maybe they didn't paste correctly.
8 0
2 years ago
Answer please need help
a_sh-v [17]

Answer:

-7

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which of the following equations have exactly one solution?
Sonja [21]

Answer:

B.

Step-by-step explanation:

Because if you subtract 19x and 18 from each side it wont be 0=0, in other equatins there is infinity solutions

7 0
2 years ago
What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4) and D(5,2)?
Dmitry_Shevchenko [17]
I think its going to be around B or D
6 0
2 years ago
Read 2 more answers
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