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Arada [10]
1 year ago
12

During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60÷5 60 ÷ 5 in this context. Fi

nd the quotient. Explain what the quotient would mean in each of the two interpretations you described. Consider the division expression 712÷2 7 1 2 ÷ 2 . Select all multiplication equations that correspond to this division expression. 2⋅?=712 2 ⋅ ? = 7 1 2 712⋅?=2 7 1 2 ⋅ ? = 2 2⋅712=? 2 ⋅ 7 1 2 = ? ?⋅712=2 ? ⋅ 7 1 2 = 2 ?⋅2=712
Mathematics
1 answer:
Afina-wow [57]1 year ago
8 0

The second question:

Consider the division expression 7\frac{1}{2} / 2. Select all multiplication equations that correspond to this division expression.

2 * ? = 7\frac{1}{2}     7\frac{1}{2} * ?= 2     ? * 2  = 7\frac{1}{2}

2* 7\frac{1}{2} = ?    ?  * 7\frac{1}{2} = 2

Answer:

1. See Explanation

2. 2 * ? = 7\frac{1}{2}     and     ? * 2  = 7\frac{1}{2}

Step-by-step explanation:

Solving (a):

Given

Students = 60

Group = Equal\ Sized

Required

Interpret \frac{60}{5} in 2 ways

<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

Quotient = \frac{60}{5}

Quotient = 12

<u>For Interpretation 1:</u>

The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

7\frac{1}{2} / 2

Required

Select all equivalent multiplication equations

Let ? be the quotient of t 7\frac{1}{2} / 2

So, we have:

7\frac{1}{2}/2 = ?

Multiply through by 2

2 * 7\frac{1}{2}/2 = ? * 2

7\frac{1}{2} = ? * 2

Rewrite as:

? * 2 = 7\frac{1}{2}  --- This is 1 equivalent expression

Apply commutative law of addition:

2 * ? = 7\frac{1}{2}  --- This is another equivalent expression

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Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

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January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

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