Ask question

Ask question

All categories

2 years ago

5

Un consejo de estudiantes de un colegio de bachillerato tiene un representante de cada grado. Si cada uno de los miembros del co

nsejo está en capacidad de ocupar cualquier cargo,si se sabe que el presidente debe ser de grado décimo o de grado undécimo, El número de formas en que se pueden seleccionar el presidente, el vicepresidente y el secretario es

1 answer:

Pepsi [2]2 years ago

6 0

Answer:

?????????

Step-by-step explanation:

You might be interested in

∠A and ∠C are right angles. m∠p = _???_ degrees.

iogann1982 [59]

Answer

Find out the m∠p .

To prove

As in ΔDAB is a right triangle

Apply pythagorean theorem

Hypotenuse ² = Perpendicular ² + Base²

DB² = AB² + AD²

AB = 5 units

AD = 6 units

Put in the above formula

DB² = 5² + 6²

= 25 + 36

= 61

$DB = \sqrt{61}\ units$

= 7.8 units (approx)

Now in ΔDCB is a right triangle .

By using the trignometric identity .

$cosp = \frac{Base}{Hypotenuse}$

$cosp = \frac{DC}{DB}$

As DC = 4 units

DB = 7.8 units (approx)

Put all the values in the trignometric identity .

$cos p = \frac{4}{7.8}$

$\angle p = cos^{-1}(\frac{4}{7.8})$

∠p = 59.15 ° (approx)

5 0

2 years ago

Read 2 more answers

In the Venn diagram, the blue circle represents when p is true, and the orange represents when q is true. A conjunction is true

Radda [10]

Answer:

A conjunction is true in region

✔ B <--- Answer

A disjunction is true in region(s)

✔ A, B, and C <--- Answer

A disjunction is false in region(s)

✔ D <--- Answer

Step-by-step explanation:

I took the assaignment aswell

3 0

2 years ago

Read 2 more answers

A bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than One-fifth? Select thr

AlladinOne [14]

Answer:

first one and last two

Step-by-step explanation:

B)

3 0

2 years ago

Read 2 more answers

Analyze the diagram to complete the statements. The m∠MXN is the m∠YZX. The m∠LZX is the m∠ZYX + m∠YXZ. The m∠MYL is 180° − m∠ZY

Xelga [282]

By using the picture that was provided below, you can see that

m<MXN is greater than m<YZX.

Angles m<LZX is equal to m<ZYX + m<YZX and

m<MYL is equal to 180 degrees minus M<ZYX.

I hope this helps! Have a good day

8 0

2 years ago

Read 2 more answers

According to a Yale program on climate change communication survey, 71% of Americans think global warming is happening.† (a) For

SpyIntel [72]

Answer:

a) 0.2741 = 27.41% probability that at least 13 believe global warming is occurring

b) 0.7611 = 76.11% probability that at least 110 believe global warming is occurring

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$p = 0.71$

(a) For a sample of 16 Americans, what is the probability that at least 13 believe global warming is occurring?

Here $n = 16$ , we want $P(X \geq 13)$ . So

$P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 13) = C_{16,13}.(0.71)^{13}.(0.29)^{3} = 0.1591$

$P(X = 14) = C_{16,14}.(0.71)^{14}.(0.29)^{2} = 0.0835$

$P(X = 15) = C_{16,15}.(0.71)^{15}.(0.29)^{1} = 0.0273$

$P(X = 16) = C_{16,16}.(0.71)^{16}.(0.29)^{0} = 0.0042$

$P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) = 0.1591 + 0.0835 + 0.0273 + 0.0042 = 0.2741$

0.2741 = 27.41% probability that at least 13 believe global warming is occurring

(b) For a sample of 160 Americans, what is the probability that at least 110 believe global warming is occurring?

Now $n = 160$ . So

$\mu = E(X) = np = 160*0.71 = 113.6$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{160*0.71*0.29} = 5.74$

Using continuity correction, this is $P(X \geq 110 - 0.5) = P(X \geq 109.5)$ , which is 1 subtracted by the pvalue of Z when X = 109.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{109.5 - 113.6}{5.74}$

$Z = -0.71$

$Z = -0.71$ has a pvalue of 0.2389

1 - 0.2389 = 0.7611

0.7611 = 76.11% probability that at least 110 believe global warming is occurring

3 0

2 years ago