Answer:
The probability that exactly 15 defective components are produced in a particular day is 0.0516
Step-by-step explanation:
Probability function : 
We are given that The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20.
So,
we are supposed to find the probability that exactly 15 defective components are produced in a particular day
So,x = 15
Substitute the values in the formula :



Hence the probability that exactly 15 defective components are produced in a particular day is 0.0516
Answer:
From the figure, it can be seen that the mage A'B'C' is obtained from the pre-image ABC by translating/shifting the vertices of the image by 7 units to the right and 6 units down.
Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is (x, y) → (x + 7, y – 6).
Answer: The coordinates of point C after the dilation are (-2, 5)
Step-by-step explanation:
I guess that you want to find where the point C ends after the dilation.
Ok, if we have a point (x, y) and we do a dilation with a scale A around the point (a,b), then the dilated point will be:
(a + A*(x - a), b + A*(y - b))
In this case we have:
(a,b) = (2,1) and A = 3.
And the coordinates of point C, before being dilated, are: (1, 2)
Then the new location of the point C will be:
C' = (1 + 3*(1 - 2), 2 + 3*(2 - 1)) = (1 -3, 2 + 3) = (-2, 5)
Answer:
5m/s;
6 seconds
Step-by-step explanation:
Given the following :
Initial position = 30 m below
He climbed at a constant rate, and was 7.5 m below after 4.5 s.
Distance climbed or covered in 4.5 seconds :
(Initial position - current position)
(30 - 7. 5)m = 22.5 meters
Using the relation:
Speed = distance covered / time taken
Therefore,
Shota's speed = 22.5m / 4.5s = 5m/s
Time taken to reach edge of volcano :
Distance left to cover = 7.5m
Speed = 5m/s
Time required to cover remaining distance :
= distance / speed
= (7.5m ÷ 5m/s) = 1.5s
Total time to reach edge :
(4.5 + 1.5)s = 6 seconds
Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7