Ask question

Ask question

All categories

2 years ago

6

A teacher noticed 5/8 of the students were wearing either blue shorts or white shorts. Write two different ways this could be do

ne

1 answer:

lukranit [14]2 years ago

3 0

3/8 could be wearing blue shorts and 2/8 could be wearing white shorts
4/8 could be wearing white shorts and 1/8 could be wearing blue shorts

You might be interested in

el dividendo en una division exacta es toma el valor de 240 halle el valor del cociente si el divisor es una unidad menor que el

baherus [9]

Tal vez deberia buscar las respuestas en internet

7 0

1 year ago

Ria can paint a room in 4 hours. Destiny can paint the same room in 6 hours. How long would it take Ria and Destiny to paint the

Lerok [7]

Time taken by Ria to paint a room = 4 hours

Time taken by Destiny to paint a room = 6 hours

If they work together, they complete 1 job. So,

$\frac{1x}{4}+\frac{1x}{6}=1$

The LCD of 4 and 6 is 12

$\frac{3x+2x}{12}=1$

$\frac{5x}{12}=1$

$5x=12$

$x=\frac{12}{5}$

Hence, both of them can paint the room in $\frac{12}{5}$ hours or 2.4 hours.

4 0

2 years ago

Read 2 more answers

Finn and Ellie sell oranges at a produce stand. Finn earns $5 for each crate of oranges he sells. At the end of the week, Ellie

Alex777 [14]

Answer:

4

Step-by-step explanation:

4x5=20

6 0

1 year ago

Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len

Marina86 [1]

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]± $Z_{1-\alpha/2}$ *(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

6 0

2 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

2 years ago