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alina1380 [7]
2 years ago
14

Fancy goldfish x cost $3 each and common goldfish y cost $1 each.Graph the function y=20-3x to determine how many of each type o

f goldfish Tasha can buy for $20.
Mathematics
1 answer:
aniked [119]2 years ago
4 0

The pairs of goldfish Tasha can buy for $20 are (0,20), (1,17), (2,14),

(3,11),(4,8),(5,5),and (6,2)

Step-by-step explanation:

To find the how many type of goldfish that Tasha can buy for $20 is the set of positive ordered pairs.

Let x denote the number of fancy goldfish.

Let y denote the number of common goldfish.

To find how much goldfish can Tasha buy for $20 is to substitute the value for x in the equation y=20-3x

Now, substituting x=0 in y=20-3x, we get,

y=20

The ordered pair is (0,20)

Similarly, substituting x=1,

y=20-3(1)\\y=20-3\\y=17

For x=2,

y=20-6\\y=14

For x=3,

y=20-9\\y=11

For x=4,

y=20-12\\y=8

For x=5,

y=20-15\\y=15

For x=6,

y=20-18\\y=2

Thus, the pairs of goldfish Tasha can buy for $20 are (0,20), (1,17), (2,14),(3,11),(4,8),(5,5),and (6,2)

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30-100/1000*120

Step-by-step explanation:

Source: Khan Academy

3 0
2 years ago
Lyles height is twice the difference of the height of his brother, harry, and the height of his dad, vince. Lyle is 2 1/2 feet t
Greeley [361]

Answer:

5 = 19 - 4v

Step-by-step explanation:

We are given the following in the question:

\text{Lyle's height} = 2( \text{Harry's height - Vince's height})

Let l be Lyle's height, h be Harry's height and v be Vince's height.

Thus, we can write:

l = 2(h-v)

Lyle's Height =

2\dfrac{1}{2}\text{ feet}

Harry's height =

4\dfrac{3}{4}\text{ feet}

Putting the value in the equation:

2\dfrac{1}{2} = 2(4\dfrac{3}{4}- v)\\\\\dfrac{5}{2} = \dfrac{19}{2} - 2v\\\\5 = 19 - 4v\\4v = 19-5\\\\v = \dfrac{14}{4}\\\\v = 3\dfrac{2}{4} = 3\dfrac{1}{2}

Thus, Vince's height is 3.5 feet.

7 0
2 years ago
Wanahton is cooking a breadstick on a rectangular baking sheet measuring 9\dfrac129
salantis [7]

<u><em>Answer:</em></u>

The longest bread stick is approximately 16 in

<u><em>Explanation:</em></u>

The diagram representing the tray is shown in the attached image

From the diagram, we can note that the diagonal of the tray represents the hypotenuse of a right-angled triangle having legs 9.5 in and 13 in

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c² = a² + b²

where c is the length of the hypotenuse and a and b are the length of the two legs

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c² = (9.5)² + (13)² = 259.25

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The longest bread stick that can be fit straight along the diagonal of the tray is approximately 16 in

Hope this helps :)

7 0
2 years ago
Mr. Gonzales has only $42.50 to spend at a clothing store. He wants to buy a shirt that costs $29, including tax, and some brace
lisabon 2012 [21]

Answer: The equation is $29 + x*$4.50 = $42.50, and the solution is x = 3

Step-by-step explanation:

The data we have is:

Gonzales has $42.50

He wants to buy:

a shirt that costs $29

some bracelets that cost $4.50 each.

The equation that we need to solve is:

Total cost = money that Gonzales has.

The cost is $29 + x*$4.50

where x is the number of bracelets he can buy.

The equation that we need to solve is:

$29 + x*$4.50 = $42.50

to solve it we must isolate x:

x*$4.50 = $42.50 - $29 = $13.50

x = 13.50/4.50 = 3

So we have that Mr. Gonzales can buy a total of 3 bracelets.

8 0
1 year ago
Read 2 more answers
If cos Θ = square root 2 over 2 and 3 pi over 2 &lt; Θ &lt; 2π, what are the values of sin Θ and tan Θ?
KIM [24]

Answer:

The answer is

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tan(\theta)=-1

Step-by-step explanation:

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

sin^{2}(\theta)+cos^{2}(\theta)=1

In this problem we have

cos(\theta)=\frac{\sqrt{2}}{2}

\frac{3\pi}{2}

so

The angle \theta belong to the third or fourth quadrant

The value of sin(\theta) is negative

Step 1

Find the value of  sin(\theta)

Remember

sin^{2}(\theta)+cos^{2}(\theta)=1

we have

cos(\theta)=\frac{\sqrt{2}}{2}

substitute

sin^{2}(\theta)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(\theta)=1-\frac{1}{2}

sin^{2}(\theta)=\frac{1}{2}

sin(\theta)=-\frac{\sqrt{2}}{2} ------> remember that the value is negative

Step 2

Find the value of tan(\theta)

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=-\frac{\sqrt{2}}{2}

cos(\theta)=\frac{\sqrt{2}}{2}

substitute

tan(\theta)=\frac{-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}

tan(\theta)=-1

8 0
2 years ago
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