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KengaRu [80]
2 years ago
14

Ryan has a $3000 bond with a 6% coupon. How much interest wil Ryan receive for this bond every 6 months

Mathematics
2 answers:
katen-ka-za [31]2 years ago
8 0

I know 6% of $3000 is $180

But I don't understand the rest of the question.


Savatey [412]2 years ago
7 0

Assuming Ryan has to pay the $3000 bond every 6 months, he would need to pay $2820.

Here is my reasoning:

6% of $3000 is $180.

Since the 6% off is a coupon, that would mean Ryan would get $180 off his $3000 bond.

Which means Ryan should have to pay $2820. ($3000 - $180 coupon).

I hope this is what you mean! If not, let me know and I will fix my answer! Have a great night Shalla9gomez! :)

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iogann1982 [59]
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:
y = \sqrt{x + 11}
Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
6 0
2 years ago
Fill in missing information to make the equality true: <br> (... +2a)2 = … +12ab2+4a2.
BigorU [14]

Answer:

I suppose it should be

6b² and (6b²)²

or

6b² and 36b^{4}

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

therefore

(6b²+2a)² = (6b²)² + 12ab² + 4a²

3 0
2 years ago
Read 2 more answers
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
strojnjashka [21]

Answer:

a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

a= μ-3.16*σ , b= μ+3.16*σ

b) P(Y≥ μ+3*σ ) ≥ 0.90

b= μ+3*σ

Step-by-step explanation:

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

5 0
2 years ago
Solve for x if 2(5x+2)^2=48
likoan [24]
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divide both sides by 2
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square root both sides to clear the power of two.
5x + 2 = + - sqrt24
subtract 2 from both sides
5x = -2 + - sqrt 24
divide both sides by 5
x = (-2 +-sqrt24)/5 or decimal answers .58 and -1.38
7 0
2 years ago
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Sergio [31]
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<span>multiply by 2/5 </span>

<span>ratio : 1 : 6/25 (1 unit of soda to 6/25 units of pineapple)</span>
8 0
2 years ago
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