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Vadim26 [7]
2 years ago
8

In the diagram, points E, A, and B are collinear and the areas of square ABCD and right triangle EAD are equal. What are the coo

rdinates of A?
A. (-7.5, 3)

B. (-8, 4)

C. (-9, 6)

D. (-8.5, 5)

E. (-6, 5)

Mathematics
2 answers:
forsale [732]2 years ago
8 0

Answer:

(-8,4)

Step-by-step explanation:

Given in the picture is a right triangle and a square sharing one commonside

Area of triangle = area of square

ie 1/2 bs = s^2 (is s is one side of square)

i.e. b = 2s where b = EA

In other words A divides line EB in the ratio 2:1

Using section formula

Coordinates of A=

(\frac{2(-7)+1(-10)}{3} ,\frac{2(2)+1(-8)}{3})\\=(-8, 4)

Zielflug [23.3K]2 years ago
6 0

Answer:

(B) -8,4

Step-by-step explanation:

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Since x^2 is the square of x and 6x is twice the product between x and 3, the second square must be 3 squared, i.e. 9.

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2 years ago
The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The
ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

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Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

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150 + 51x < 100 + 55x

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51x-55x

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