First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,
x = 2/3(x+2.5)
x = 2/3 x + 5/3
1/3 x = 5/3
x = 5 km
Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,
Total distance = 2(5km) + 7.5 km
Total distance = 17.5 km
Answer:perpendicular bisector theorem
Step-by-step explanation:
Answer:
There is not sufficient evidence to warrant the rejection of the claim that the mean weight of cereal is atleast 14 oz
Step-by-step explanation:
The hypothesis for the test above will be stated as follows :
The claim to be tested is the alternative hypothesis, which is the negation of the Null hypothesis
H0 : μ < 14
H1 : μ ≥ 14
If the Null is rejected, then it means that the company's claim that the mean weight of its cereal being atleast 14 is valid ;
Then it means there is significant evidence to support the stance that the mean weight of cereal in the company's packet is atleast 14 oz.
We know that
Half-life is modeled by the formula
An=A0*(0.5)<span>^[t/h)]
where
An----------> </span>is the amount remaining after a time t
A0----------> is the initial quantity
t------------> is the time
h------------> is the half-life of the decaying quantity
in this problem
h=1601 years
A0=50 g
An=?
t=100 years
An=A0*(0.5)^[t/h)]---------> An=50*(0.5)^[100/1601)]-----> 47.88 gr
the answer is 47.88 g
Answer:

Step-by-step explanation:
The conic form of the equation for a sideways parabola is
(y - k)² = 4p(x - h)
The focus is at (h + p, k)
The equation of Samara's parabola is
(y - 3)² = 8(x - 4)
h = 4
p = 8/4 = 2
k = 3
h + p = 6
So, the focus point of the satellite dish is at
