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kkurt [141]
2 years ago
10

Esmerelda rents a car from a company that rents cars by the hour. She has to pay an initial fee of $52, and then they charge her

$8 per hour. She has $144 available on spend on a car rental. What is the greatest number of hours for which she can rent the car?
A.18 hours
B.12 hours
C.11.5 hours
D.11 hours
Mathematics
1 answer:
Kisachek [45]2 years ago
6 0

C

first set up an equation

$52+8n ≥ 144

bacause she can spend 144 or less

solve 144-52=92

92/8=11.5

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Ester's choir wants to learn a new song for the school concert in 7 weeks. The song has 3016 lines. The choir learns an equal nu
andriy [413]

Hello!

We are asked to find the number of lines the choir has to learn in time for a concert.

We're given that the concert is in 7 weeks, but they learn new lines each day, so we have to convert it to days. We know that there is 7 days in a week, we would multiply 7 weeks by 7 days, which is 49 days.

Now, we would take the total number of lines, which is 3016, and divide that by 49 days.

3016 lines / 49 days ≈ 61.55 lines/day

Since this is a real-world situation, we should round our answer is to nearest whole number, which would be 62 lines/day.

Therefore, Ester's choir needs to learn about 62 lines per day in time for the concert.

3 0
2 years ago
What is the equation of the graph below?
kherson [118]

Answer:

A. y = sine (x + 90 degrees)

Step-by-step explanation:

  • y = cosine(x) is a curve that crosses the y-axis at y = 1 and completes one cycle at 360 degrees.
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  • f(x + c) translates f(x) horizontally c units to the left.
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7 0
2 years ago
Read 2 more answers
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
shepuryov [24]
The probability that both the chosen students are sophomores is 6/20 or 3/10 simplified.
the expresión that represents the probability that both students have chosen are sophomore is (6c1) (5c1) /(20c2) 

5 0
2 years ago
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The graph shows the solution to the initial value problem y'(t)=mt, y(t0)= -4
Charra [1.4K]
y'(t)=mt
\\
\\ y=\int {mt} \, dt=m \int{t} \,dt=m \frac{t^2}{2} +C \\ \\y= \frac{mt^2}{2}+C

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.

y=at^2+b
\\
\\3=a\times 2^2-2
\\
\\3=4a-2
\\
\\5=4a
\\
\\a= \frac{5}{4} 
\\
\\y=\frac{5}{4} t^2-2 \\ \\y= \frac{m}{2} t^2+C
\\ \\  \frac{m}{2} = \frac{5}{4} 
\\
\\m= \frac{5}{2} 
\\
\\C=-2
\\
\\y(t_0)=-4
\\
\\-4= \frac{5}{4} t_0^2-2
\\
\\ -2= \frac{5}{4} t_0^2
\\
\\ t_0^2=- \frac{8}{5} 
\\
\\t_0=\pm \sqrt{- \frac{8}{5} }



3 0
2 years ago
Teresa says that because the diagonals of a parallelogram bisect each other, if one diagonal is 4.2 cm, the other diagonal must
saw5 [17]

Answer:

See it in the pic.

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See it in the pic.

3 0
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