Answer:
$(55-3m) is the amount of money she has left
Step-by-step explanation:
In this question, we are asked to give an expression to represent how much money was left after Sarah had bought some certain stuffs at some prices using the money she received at her birthday.
Firstly, we identify that the total amount of money she has to spend is $55.
Now let’s project her total spendings. She bought 3 shirts with each shirt costing $m.
The total amount spent on the shirts is thus; 3 * $m = $3m
The amount of money she has left is the difference.
Mathematically, this is equal to $55 - $3m
Answer:
The area of larger table is 24 square feet.
Step-by-step explanation:
Given are the length and width of small table

The area of a rectangular table is calculated by multiplying the length and width. It is also given that the length and width of the larger table is double the length and width of small table
So the length and width of larger table will be:

The area of larger table will be:

Hence,
The area of larger table is 24 square feet.
The answer is 8 marbles. 6*8=48. 48(ednas marbles) + 8(sam's marbles)=56.
Answer:
See below.
Step-by-step explanation:
Well first, we need to find the weight of the table. We know that 8 boxes weighs a total of 240kg (since each box weights 30kg). Thus, we can conclude that the table weighs 70kg by doing 310-240=70.
Now, we can write our function. Let
equal the amount of boxes.
The table is a set weight, so that would be our constant.
Thus, we will have:

30x represents the weight each box of book adds to the total. One box equals 30kg, 2 boxes equal 60kg, etc.
The 70 represents the unchanging weight of the table.
In terms of W(x), it will be:

<span> Honor roll Not on honor roll Total
Received math class requested 315 64 379
Did not get math class requested 41 80 121
Total 356 144 500
Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%
Honor roll students were given preference in granting request than those not in the honor roll.</span>