15% of $45 is $6.75
I'm assuming this was the answer to yur question?
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5% of $45 is $2.25
5% of $2.25 is $0.1125
Answer:
Yes, Renaldo will be reach on time for his Soccer practice.
Step-by-step explanation:
For traveling for 3.2 miles bus takes 30 minute times.
So, traveling a 1-mile bus will take 30 ÷ 3.2 minutes.
Now, Renaldo reaches the dentist's office at 4:30 p.m.
Then he has an appointment for 1 hour
So, Renaldo leaves the dentist's office at 5:30 p.m.
Now he has to travel 4.8 miles, it will take time = 
So, Renaldo will reach Soccer field at
5 hours 30 minute + 45 minutes = 6 hours 15 minutes = 6:15 p.m
Hence, Renaldo will reach Soccer field before 6:30 p.m.
Answer: You can use this to help you out:
Determine the term life insurance amount per thousand on a 20-year-old male for a 10-year policy given that the face value of the policy is $65,000 and the annual premium is $291.85.
a.
$0.00449
c.
$0.2227
b.
$4.49
d.
$222.72
First find how many thousands on the amount of the face value
You do that by dividing the amount of the face value by 1000
65,000÷1,000=65
So the term life insurance amount per thousand is
291.85÷65=4.49...answer
Read more on Brainly.com - brainly.com/question/4241979#readmore
Answer:
a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution
b. The degrees of freedom do you have for this test is 4
c. The calculated value of the test statistic is 9.250
Step-by-step explanation:
a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.
b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:
degrees of freedom=k-1
degrees of freedom=5-1
degrees of freedom=4
c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:
expected frecuency=total observed frecuency/total number of category
expected frecuency=1,000/5
expected frecuency=200
Hence, to calculate the value of the test statistic we have to calculate the following formula:
x∧2=∑(fo-fe)∧2/fe
=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2
=9.250
The calculated value of the test statistic is 9.250
^ if you're talking universally, no it would be cm. But no one really says "quarter inches". You would just say inches
