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blondinia [14]
2 years ago
15

the class kept track of rainy and sunny days. During the 54 days, classified rainy or sunny, the ratio of rainy days is 7 to 14.

How many sunny days were there?
Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0

There are 36 sunny days

baherus [9]2 years ago
4 0

1:2

1 + 2 = 3

54/3 = 18

1 • 18 = 18

2 • 18 = 36

There are 36 sunny days.

Hope this helps!

If it does then I would appreciate it if you could make me brainliest.

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Your Answer is 14.50.b is 27
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In your problem:
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The first few steps in solving the quadratic equation 9x2 + 49x = 22 − 5x by completing the square are shown. 9x2 + 49x = 22 − 5
Vladimir79 [104]

Answer:

9x²+49x=22-5x

==>9x²+54x-22=0

==>9(x²+2*3x+9)-22-81=0

==>9(x+3)²-103=0

5 0
2 years ago
Read 2 more answers
The Parsons have a balance of $3,664.47 in their check register. On their bank statement, the balance on the account is $2,346.8
Lapatulllka [165]
$2,346.89 + $500 + $1,456.81 = $4,303.70

$4,303.70 - $324.56 - $25.50 - $78.92 - $30.25 - $60 - $60 - $60 = $3,664.47

$3,664.47 is exactly what they have in their checkbook.
5 0
2 years ago
If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?
Alborosie

No, not possible to tell that the the two triangles, ΔBAC and ΔCED

are similar ⇒ answer D

Step-by-step explanation:

Let us revise the cases of similarity

1. AAA similarity : two triangles are similar if all three angles in the first

  triangle equal the corresponding angle in the second triangle  

2. AA similarity : If two angles of one triangle are equal to the

   corresponding angles of the other triangle, then the two triangles  

   are similar.

3. SSS similarity : If the corresponding sides of the two triangles are

   proportional, then the two triangles are similar.

4. SAS similarity : In two triangles, if two sets of corresponding sides  

   are proportional and the included angles are equal then the two  

   triangles are similar.

In the two triangles BAC and CED

∵ m∠BAC = 17°

∵ m∠CED = 17°

∴ m∠BAC = m∠CED

But we need another pair of angles to prove that the two triangles are

similar by AA similarity criterion

<em>OR </em>

The lengths of sides BA , CA and CE , DE to show that

\frac{BA}{CE}=\frac{CA}{DE} = constant ratio and prove that the

two triangles are similar by SAS similarity criterion

So it is not possible to prove that the two triangles are similar

No, not possible to tell that the the two triangles, ΔBAC and ΔCED

are similar

Learn more:

You can learn more about triangles in brainly.com/question/4354581

#LearnwithBrainly

5 0
2 years ago
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