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Amiraneli [1.4K]

2 years ago

10

Fernando is playing basketball. He has made 18 free throws out of 30 attempts. At this rate, how many of Fernando's next 50 free

throws should he expect to make?

1 answer:

docker41 [41]2 years ago

3 0

The answer is 38/50 and there's the work^^

You might be interested in

Zucchini plants require 9 square feet around each plant.

MrRa [10]

The area of square TUVW = 3×3 = 9 square units

1 square unit = 4 head lettuces
9 square units = 9×4 = 36 lettuces

Area of plot QRST = length × width = 12×6 = 72 square units

36 vegetables for every 9 square units
We have 72÷9 = 8 lots of 9 square units

Total vegetable = 8 × 36 = 288 vegetables

We can have 8 different vegetables, each type can have 36 vegetables

4 0

1 year ago

A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The

lisov135 [29]

Answer:

$(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96$

$(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96$

And the confidence interval would be given by:

$-1.96 \leq \mu_1 -\mu_2 \leq 7.96$

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

Step-by-step explanation:

For this case we have the following info given :

$\bar X_1= 75.1$ represent the sample mean for the scores of the undergraduate students

$s_1 = 12.8$ represent the standard deviation for the undergraduate students

$n_1 =35$ the sample size for the undergraduate

$\bar X_2= 72.1$ represent the sample mean for the scores of the high school students

$s_2 = 14.6$ represent the standard deviation for the high school students

$n_2 =50$ the sample size for the high school

The confidence interval for the true difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given by:

$df=n_1 +n_2 -2= 35+50-2=83$

The confidence level is 90% and the significance level is $\alpha=0.1$ and $\alpha/2 =0.05$ then the critical value would be:

$t_{\alpha/2}= 1.99$

And replacing the info we got:

$(75.1 -72.1) -1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= -1.96$

$(75.1 -72.1) +1.66 \sqrt{\frac{12.8^2}{35} +\frac{14.6^2}{50}}= 7.96$

And the confidence interval would be given by:

$-1.96 \leq \mu_1 -\mu_2 \leq 7.96$

And since the confidence interval contains the value 0 we have enough evidence to conclude that we don't have significant differences between the two means at 10% of significance.

8 0

1 year ago

5.44 Teaching descriptive statistics: A study compared five different methods for teaching descriptive statistics. The five meth

maria [59]

Answer:

The null hypothesis is that all the different teaching methods have the same average test scores.

H0: μ1 = μ2 = μ3 = μ4 = μ5

The alternative hypothesis is that at least one of the teaching methods have a different mean.

Ha: at least one mean is different. (μ1 ≠ μi)

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above, let μ represent the average test scores for the teaching methods:

The null hypothesis is that all the different teaching methods have the same average test scores.

H0: μ1 = μ2 = μ3 = μ4 = μ5

The alternative hypothesis is that at least one of the teaching methods have a different mean.

Ha: at least one mean is different. (μ1 ≠ μi)

7 0

1 year ago

Clay can run one lap around the track in 1/4 of an hour. How many hours will it take him to run 5 1/3 laps around the track?

Jet001 [13]

Answer: It will take him 1 hour and 35 min

8 0

1 year ago

A California distributor of sporting equipment expects to sell 10,000 cases of tennis balls during the coming year at a steady r

sleet_krkn [62]

Economic Order Quantity

The economic order quantity, that is, the order quantity that minimizes the inventory cost is:

300 cases of tennis balls

Data and Calculations:

Sales of tennis balls for the coming year = 10,000 units

Carrying (holding) costs per case = $10

Cost of placing orders with the manufacturer = $45 per order

Economic Order Quantity (EOQ) = square root of (2 * Annual Demand/Sales * Ordering cost)/Carrying cost per case

= square root of (2 * 10,000 * $45)/$10

= square root of 90,000

= 300 tennis balls

This implies that the distributor will place about 33 orders in the coming year. With each order, the quantity placed is 300 units. This is the economic order quantity that will minimize its inventory cost for the year.

8 0

2 years ago