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12345 [234]
2 years ago
9

A fair sortition trial is carried out, and one of the candidates is assigned the number 32,041. If each digit can be chosen from

0-4, and if each of the possible sequences is assigned to a candidate, how many candidates are there?
Mathematics
2 answers:
erik [133]2 years ago
6 0
The answer to this question is 3,125
Kitty [74]2 years ago
3 0

Answer: 3125


Step-by-step explanation:

Given: A fair sortition trial is carried out, and one of the candidates is assigned the number = 32,041

If each digit can be chosen from 0-4, and if each of the possible sequences is assigned to a candidate, then the number of candidates (repetition of digits allowed)=5\times5\times5\times5\times5

=3125

Hence, the number of candidates there are = 3125.




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The square shown has a perimeter of 32 units. The square is rotated about line k.
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A cylinder with a circumference of about 50 units is formed.

Step-by-step explanation:

Step 1:

The perimeter of the square is 32 units. The perimeter of a square is given by 4 times its side length.

(4) sidelength = 32, sidelength = \frac{32}{4} = 8.

So the side length of the square is 8 units.

If a square is rotated a cylinder will be formed. So the options with a cone are wrong as a cone is formed when a triangle is rotated.

Step 2:

To calculate the circumference of the cylinder, we multiply 2π with the radius. The radius is the same as the side length of the square. So r is 8 units.

The circumference of the cylinder = 2\pi r = (2) (3.1415)(8) = 50.264.

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2 years ago
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Point Y is the midpoint of segment XZ. If XY = 2(3x +1) and YZ = 5x + 22, find the value of x.
Ede4ka [16]
<h3>Point Y is the midpoint of segment XZ. Then value of x is 20</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>Point Y is the midpoint of segment XZ</u></em>

XY = 2(3x +1)

YZ = 5x + 22

To find: Value of x

Since, Point Y is the midpoint of segment XZ,

Therefore,

XY = YZ

2(3x + 1) = 5x + 22

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Answer:

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

Step-by-step explanation:

The explanation of given question is described below:

Here, the test of hypothesis states that

H_o : Mean = 28.6

H_a : Mean\ which\ is\ not\ equals\ 28.6

The test statistic is

Z = \frac{(\bar X - Mean)}{\frac{Population\ standard\ deviation}{vn} }

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According to the given data α = 0.05,

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IZ(0.025)I = 1.96

(refer to the standard normal table) .

Finally

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

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