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AlekseyPX
2 years ago
6

2x+5y=-6 , wht is the x intercept, what is the y intercept

Mathematics
1 answer:
Arlecino [84]2 years ago
7 0
These are the <span>xx</span> and <span>yy</span> intercepts of the equation <span><span>2x−5y=6</span><span>2x-5y=6</span></span>.x-intercept: <span><span>(3,0)</span><span>(3,0)</span></span>y-intercept: <span>(0,−<span>65</span><span>)

</span></span>
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The graph shows the distance in miles of a runner over x hours. What is the average rate of speed over the interval [9, 11]?
JulsSmile [24]
For this case what you should see is that for the interval [9, 11] the behavior of the function is almost linear.
 Therefore, we can find the average rate of change as follows:
 m = (y2-y1) / (x2-x1)
 m = (11-6) / (11-9)
 m = (5) / (2)
 m = 5/2
 Answer:
 the average rate of speed over the interval [9, 11] is: 
 D. 5 / 2
8 0
1 year ago
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In isosceles △ABC (AC = BC) with base angle 30° CD is a median. How long is the leg of △ABC, if sum of the perimeters of △ACD an
SIZIF [17.4K]

Note necessary facts about isosceles triangle ABC:

  • The median CD drawn to the base AB is also an altitude to tha base in isosceles triangle (CD⊥AB). This gives you that triangles ACD and BCD are congruent right triangles with hypotenuses AC and BC, respectively.
  • The legs AB and BC of isosceles triangle ABC are congruent, AC=BC.
  • Angles at the base AB are congruent, m∠A=m∠B=30°.

1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.

AC=2CD.

2. Consider right triangle BCD. The adjacent angle to the leg BD is 30°, so the hypotenuse BC is twice the opposite leg CD to the angle B.

BC=2CD.

3. Find the perimeters of triangles ACD, BCD and ABC:

P_{ACD}=AC+CD+AD=2CD+CD+AD=3CD+AD;

P_{BCD}=BC+CD+BD=2CD+CD+AD=3CD+AD;

P_{ABC}=AC+BC+AB=2CD+2CD+AD+BD=4CD+2AD.

4.  If sum of the perimeters of △ACD and △BCD is 20 cm more than the perimeter of △ABC, then

P_{ACD}+P_{BCD}=P_{ABC}+20,\\ \\3CD+AD+3CD+AD=4CD+2AD+20,\\ \\6CD+2AD=4CD+2AD+20,\\ \\2CD=20.

5. Since AC=BC=2CD, then the legs AC and BC of isosceles triangles have length 20 cm.

Answer: 20 cm.

8 0
2 years ago
Read 2 more answers
In the expression " 5.3t - (20÷4) + 11" what part is a quotient? Describe its parts.​
enyata [817]

Answer:

(20 divided by 4) is the quotient

Step-by-step explanation:

4 0
1 year ago
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Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av
Brrunno [24]

The answer is 6(0.65-t)

3 0
1 year ago
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On Monday, the closing value of a share of stock in Company ABC, was 74.01. On Tuesday, it closed at 73.67, and on Wednesday, it
Elenna [48]

Answer:

957.71

Step-by-step explanation:

Given: On Monday, the closing value of a share of stock in Company ABC, was 74.01. On Tuesday, it closed at 73.67, and on Wednesday, it closed at 74.32. On Thursday, the change in stock value was -1.48. And, on Friday, Company ABC's stock gained 0.89points.

To Find: One shareholder owns 13shares of Company ABC's stock. What was the total value of their stock in this company at the close of Tuesday.

Solution:

Closing value of Shares of company ABC on Monday =74.01

Closing value of Shares of company ABC on Tuesday =73.67

Closing value of Shares of company ABC on Wednesday =74.32

on Thursday change in stock value was -1.48

Closing value of Shares of company ABC on Thursday =72.84

on Friday comapny's stock gained 0.89 points

Closing value of Shares of company ABC on Friday =73.73

As one shareholder owns 13 shares of company

Total value of shares on Tuesday is

                         =\text{number of shares}\times\text{closing stock value on tuesday}

                         =13\times73.67

                         =957.71

Hence total value of shareholder's share on close of Tuesday is 957.71

6 0
1 year ago
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