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2 years ago

Given: Two concentric circles with Center Point p. How many tangent lines can be drawn that both circles share?

1 answer:

7 0

Answer: I think that it's not One but It's ZERO because a tangent line can only touch the circle at one point and if it touches the small circle once it would have to go through the larger one twice.

Edit: I just checked and it's definitely ZERO

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Pls explain your work!

mylen [45]

Answer:

find total volume to find what amount is 20%

hack, is put the 20% in alreadyy to find 20% volume

20%=1/5

vcone=1/3(hpir^2)

times thath by 1/5

vcone=1/15(hpir^2)

d/2=r

given

4.8=d

4.8/2=d/2=r=2.4

10=h

V=1/15(10pi2.4^2)

V=1/15(10pi5.76)

V=1/15(57.6pi)

V=3.84pi

V=12.0637 cubic inches=20% of vase

0.5 cubc inches per min

0.5 times t=12.0637

divide both sides by 0.5

t=24.1237

about 24 minutes

Step-by-step explanation:

6 0

2 years ago

Nicholas scoops a few gum balls into his bag when he weighs it he finds that he scooped 0.76 pounds how much will the gum balls

11111nata11111 [884]

Answer:

The cost of 0.76 pound gum ball is $2.6448

The cost of 1.5 pounds of sour patch kids is $5.985

Step-by-step explanation:

Consider the provided information.

Nicholas scoops a few gum balls into his bag when he weighs it he finds that he scooped 0.76 pounds. The cost of 1 pound of gum balls is $3.48

This can be written as:

1 pound gum ball= $3.48

Multiply both the sides by 0.76

1×0.76 pound gum ball= $3.48×0.76

0.76 pound gum ball= $2.6448

Hence, the cost of 0.76 pound gum ball is $2.6448

Nichols has decided to buy 1.5 pounds of sour patch kids and the cost of 1 pound of sour patch kids is $3.99

This can be written as:

1 pound sour patch kids = $3.99

Multiply both the sides by 1.5

1×1.5 pound sour patch kids = $3.99×1.5

1.5 pound sour patch kids = $5.985

Hence, the cost of 1.5 pounds of sour patch kids is $5.985

4 0

2 years ago

Statements about regression

galben [10]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

It is true because the square of the standard error of its estimate was its total square error divided only by the degree of freedom.
It is true because Its coefficient with Standardized Regression, beta, will have the same value as r, the approximate similarity.
It is false because Its slope b, of its equation of regression, will have the same value as r, the projected correlation.

3 0

2 years ago

A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot

Damm [24]

Answer:

a) $p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) $\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

$p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

$\hat p$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545$

$0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591$

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.

5 0

2 years ago

The average temperature for four days days was 22 degrees what must the temperature be on the fifth day in order to make 23 degr

galina1969 [7]

Answer:

27 degrees.

Step-by-step explanation:

If the average is to be 23 degrees over 5 days then the total of the temperatures will be 5*23 = 115 degrees.

The total over the first 4 days = 22*4 = 88 degrees, so the temperature on the fifth day has to be 115 - 88 = 27 degrees.

5 0

2 years ago