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Anit [1.1K]
2 years ago
14

Given f(2) = 2x – 3, find f(1).

Mathematics
1 answer:
REY [17]2 years ago
5 0
So when it asks for a function with a number in parenthesis like that it’s asking for you to find the function of that number.

Basically substitute in that number.

F(1)=2(1)-3
=2-3
=-1
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4abc + (-9abc) + 10d?
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-5abc+10d will be the answer.
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2 years ago
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A set of data points has a line of best fit of y=2.5x-1.5
castortr0y [4]

To solve this problem you must apply the proccedure shown below:

1- You must apply the following formula:

R=yo-yp

WhereR is the residual, yo is the observed value y and yp is the predicted value y.

2- You only need to substitute the x=5 into the equation y=2.5x-1.5 and then, you must apply the formula for calculate the residual:

y=2.5(5)-1.5\\ y=11

R=12-11\\ R=1

The answer is: The residual is 1

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A researcher wants to develop a product for families who have small children. He needs to determine if there is a nationwide int
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Answer:

b

Step-by-step explanation:

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2 years ago
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Each cone of the hourglass has a height of 15 millimeters. The total height of the sand within the top portion of the hourglass
BARSIC [14]
Calculate the volume of sand, the cone will be completely filled and the cylinder will have sand up to the 30 mm level.

Volume of sand will = the volume of the cone:
= 1/3 * pi * (6 mm)^2 * 15
= 1/3 * pi * 36 * 15 =180 pi cubic mm

the cylinder will have a volume of sand equal to:
= pi * (6 mm)^2 * 30 mm
= pi * 36 sq mm * 30 mm 
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The total sand is the sum:
= 1080 pi cubic mm +180 pi cubic mm
= 1260 pi cubic mm. <span>
</span>
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2 years ago
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Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is
Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

(x^2-12x+35)(x^2+10x+24)=504

We have to find the sum of positive roots of the equation.

x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504

x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504

x^4-2x^3-61x^2+62x+840-504=0

x^4-2x^3-61x^2+62x+336=0

Factor of 336

2,3,4,6,8,7,

Let x=2

2^4-2^4-61(2^2)+62(2)+336\neq0

x=2 is not the root of equation

x=-2

(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

3^4-2(3^3)-61(3^2)+62(3)+336=0

Therefore, x=3  is the root of equation.

(x+2)(x-3)(x^2-x-56)=0

(x+2)(x-3)(x^2-8x+7x-56)=0

(x+2)(x-3)(x(x-8)+7(x-8))=0

(x+2)(x-3)(x-8)(x+7)=0

x-8=0\implies x=8

x+7=0\implies x=-7

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0
2 years ago
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