1. A straight line segment can be drawn joining any two points.
2. Any straight line segment can be extended indefinitely in a straight line.
3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.
4. All right angles are congruent.
5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate.
Line is divided into 4 equal parts.
we have to find a point which is closest to point A.
So that means required point P(x,y) is at 1 unit away from A(-1,1) and 3 unit away from B(8,4)
Now we just need to use section formula to get the coordinate of required point using m1=1 and m2=3
So the final answer is 
.
Answer:
The rational function that is graphed is B
Try this solution (see the attachment, it is consists of 3 steps).
Answer:
The possible value of X are;
15, 30, 45, 60 etc
Step-by-step explanation:
The parameters given are
Number of chocolates Tanmay had = X
Number of chocolates Tanmay gave to Akash = 1/3 × X
Number of chocolates Tanmay gave to Sharad = 1/5 × X
Whereby 3 and 5 are factors of X, therefore;
3 × 5 = 15 is the lowest single factor of X
The possible values of X starting from the lowest factor are given as follows;
15 × 1 = 15
15 × 2 = 30
15 × 3 = 45
15 × 4 = 60
Hence, the possible value of X are the arithmetic progression a + (n - 1)×d
Where:
a = 15
n = 1, 2, 3, 4, ...
d = 15
Which includes;
15, 30, 45, 60
