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2 years ago

Given f(2) = 2x – 3, find f(1).

Mathematics

1 answer:

REY [17]2 years ago

5 0

So when it asks for a function with a number in parenthesis like that it’s asking for you to find the function of that number.

Basically substitute in that number.

F(1)=2(1)-3
=2-3
=-1

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Angela drove 82 miles on Monday. She drove 94 on Tuesday. To the nearest hundred, how many miles did Angela drive over the two d

inessss [21]

You just simply add
82+94= 166

4 0

2 years ago

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According to the Rational Root Theorem, which statement about f(x) = 66x4 – 2x3 + 11x2 + 35 is true? Any rational root of f(x) i

Kamila [148]

Answer:

The correct option is Any rational root of f(x) is a factor of 35 divided by a factor of 66....

Step-by-step explanation:

According to the rational root theorem:

if $a_{0}$ and $a_{n}$ are non zero then each rational solution x will be:

x= +/- Factors of $a_{0}$ / Factors of $a_{n}$

In the given polynomial we have:

66x4 – 2x3 + 11x2 + 35

$a_{0}$ = 35

$a_{n}$ = 66

Therefore,

x= +/- Factors of 35/ Factors of 66.

Thus the correct option is Any rational root of f(x) is a factor of 35 divided by a factor of 66....

3 0

2 years ago

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A cardboard popcorn container is shaped like a cone that is 11 inches high and has a radius of 2.5 inches. What is the volume of

Vika [28.1K]

Vcone=(1/3)hpir^2
h=11
r=2.5
Vcone=(1/3)11pi2.5^2
Vcone=(11/3)pi6.26
Vcone=68.75/3*3.14
Vcone=71.95833
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2 years ago

A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro

Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0

1 year ago

The graph of the logarithmic function f(x) = loga(x) passes through the points and . The graph lies the y-axis.

vagabundo [1.1K]

The question is incomplete. But this explanation will help you very much.

1) Regarding the function      $log_ax$    , its graph always passes through the points (1,0) and (a,1).

That is due to the properties of logarithm function:

a)    $log_a1=0$

b)    $log_aa=1$
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That in turn is due to the properties of the exponential functions.

a^0 = 1 and a^1 = a
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2) Regarding the y-axis.

The function $log_ax$ will never touch the y-axis, because the logaritm of zero is not defined. So the graph lies to the righ of the y-axis (i.e. the domain of the function is x > 0)

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2 years ago

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