Answer:
3/4
Step-by-step explanation:
18:24=18/24
18/24 reduces to 3/4
Let the no. Of boys=x and that of girls=y.
The total no. Of students = x+y .
As given by statement the no. Of boys=x={(x+y)/3} + 5
This implies that
X=(x+y+15)/3
Also we know that x/y = 2/3 therefore
From this equation we get x=2y/3 and y=3x/2
By method of substitution we get
X=(x+3x/2+15)/3
•x=(15x+90)/2
•2x=15x+90
•-13x=90
X= -90/13
Now. Y= 3x/2=-270/26
Therefore total
no. Of students= -270/26+(-90/13)
•no. Of students= -450/26
According to me this is an imaginary question i mean how can their be a negative person
Given functin is :
![f\left(x\right)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3D%5Csqrt%5B5%5D%7Bx%7D)
We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.
Domain: (-∞,∞)
Range is the set of y-values obtained by plugging values from domain so the range will also same.
Range: (-∞,∞)
If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.
It crosses x and y-axes both at the origin
Hence x-intercept=0 and y-intercept=0
Graph is not symmetric about y-axis hence it can't be EVEN
Graph is not symmetric about origin so it is ODD.
There is no breaking point in the graph so that means it is a Continuous function.
There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.
END behaviour means how y-changes when x approaches infinity.
From graph we can see that when x-approaches -∞ then y also approaches ∞.
when x-approaches +∞ then y also approaches +∞.
Answer:
One solution x = 2
Step-by-step explanation:
Given the equation:

Multiply this equation by 2:

Use distributive property:

Combine the like terms:

Thus, this equation has one solution x = 2
We have been given a system of inequalities and an objective function.
The inequalities are given as:

And the objective function is given as:

In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.
The graph of the region is shown below:
From the graph, we can see that corner points of the feasible region are:
(x,y) = (15,30),(30,15) and (30,60).
Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.

Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30