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zlopas [31]
1 year ago
16

On a coordinate plane, a piecewise function has 2 lines. The first line has an open circle at (0, 1) and goes up through (negati

ve 4, 3) with an arrow instead of an endpoint. The second line has a closed circle at (0, negative 2) and goes up through (2, 2) with an arrow instead of an endpoint.
Which piecewise function is shown in the graph?
f(x) = StartLayout enlarged left-brace 1st Row 1st column negative 0.5 x + 1, 2nd column x less-than 0 2nd row 1st column 2 x minus 2, 2nd column x greater-than-or-equal-to 0 EndLayout
f(x) = StartLayout enlarged left-brace 1st Row 1st column negative x + 1, 2nd column x less-than 0 2nd row 1st column 0.5 x minus 2, 2nd column x greater-than 0 EndLayout
f(x) = StartLayout enlarged left-brace 1st Row 1st column x minus 1, 2nd column x less-than-or-equal-to 0 2nd row 1st column 2 x minus 2, 2nd column x greater-than 0 EndLayout
f(x) = StartLayout enlarged left-brace 1st Row 1st column negative 0.5 x minus 1, 2nd column x less-than-or-equal-to 0 2nd row 1st column 2 x minus 2, 2nd column x greater-than-or-equal-to 0 EndLayout
Mathematics
2 answers:
aivan3 [116]1 year ago
6 0

Answer:c

Step-by-step explanation:

egoroff_w [7]1 year ago
4 0

Answer:

It was actually A on edgen.  

Step-by-step explanation:

Guest
1 year ago
CORRECT!
You might be interested in
What ratio is equivalent to the ratio 18:24
Lana71 [14]

Answer:

3/4

Step-by-step explanation:

18:24=18/24

18/24 reduces to 3/4

3 0
2 years ago
The ratio of boys to girls in a certain classroom was 2 : 3. If boys represented five more than one third of the class, how many
Tju [1.3M]
Let the no. Of boys=x and that of girls=y.
The total no. Of students = x+y .
As given by statement the no. Of boys=x={(x+y)/3} + 5
This implies that
X=(x+y+15)/3
Also we know that x/y = 2/3 therefore
From this equation we get x=2y/3 and y=3x/2
By method of substitution we get
X=(x+3x/2+15)/3
•x=(15x+90)/2
•2x=15x+90
•-13x=90
X= -90/13
Now. Y= 3x/2=-270/26
Therefore total
no. Of students= -270/26+(-90/13)
•no. Of students= -450/26
According to me this is an imaginary question i mean how can their be a negative person
6 0
2 years ago
Identify the key characteristics of the parent fifth-root function f (x) = ^5sqrtx. Include the following: domain, range, interv
Andre45 [30]

Given functin is :

f\left(x\right)=\sqrt[5]{x}

We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.

Domain: (-∞,∞)

Range is the set of y-values obtained by plugging values from domain so the range will also same.

Range: (-∞,∞)

If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.

It crosses x and y-axes both at the origin

Hence x-intercept=0 and y-intercept=0

Graph is not symmetric about y-axis hence it can't be EVEN

Graph is not symmetric about origin so it is ODD.

There is  no breaking point in the graph so that means it is a Continuous function.

There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.

END behaviour means how y-changes when x approaches infinity.

From graph we can see that when x-approaches -∞ then y also approaches ∞.

when x-approaches +∞ then y also approaches +∞.

7 0
2 years ago
How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x
Firlakuza [10]

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

\dfrac{1}{2}(x+12)=4x-1

Multiply this equation by 2:

2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)

Use distributive property:

x+12=8x-2

Combine the like terms:

x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2

Thus, this equation has one solution x = 2

7 0
2 years ago
Read 3 more answers
The graph represents the feasible region for the system:
morpeh [17]

We have been given a system of inequalities and an objective function.

The inequalities are given as:

y\leq 2x\\
x+y\leq 45\\
x\leq 30\\

And the objective function is given as:

P=25x+20y

In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.

The graph of the region is shown below:

From the graph, we can see that corner points of the feasible region are:

(x,y) = (15,30),(30,15) and (30,60).

Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.

\text{At (15,30)}\Leftrightarrow P=25\cdot 15+20\cdot 30=975\\
\text{At (30,15)}\Leftrightarrow P=25\cdot 30+20\cdot 15=1050\\
\text{At (30,60)}\Leftrightarrow P=25\cdot 30+20\cdot 60=1950\\

Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30

3 0
2 years ago
Read 2 more answers
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