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zlopas [31]
2 years ago
16

On a coordinate plane, a piecewise function has 2 lines. The first line has an open circle at (0, 1) and goes up through (negati

ve 4, 3) with an arrow instead of an endpoint. The second line has a closed circle at (0, negative 2) and goes up through (2, 2) with an arrow instead of an endpoint.
Which piecewise function is shown in the graph?
f(x) = StartLayout enlarged left-brace 1st Row 1st column negative 0.5 x + 1, 2nd column x less-than 0 2nd row 1st column 2 x minus 2, 2nd column x greater-than-or-equal-to 0 EndLayout
f(x) = StartLayout enlarged left-brace 1st Row 1st column negative x + 1, 2nd column x less-than 0 2nd row 1st column 0.5 x minus 2, 2nd column x greater-than 0 EndLayout
f(x) = StartLayout enlarged left-brace 1st Row 1st column x minus 1, 2nd column x less-than-or-equal-to 0 2nd row 1st column 2 x minus 2, 2nd column x greater-than 0 EndLayout
f(x) = StartLayout enlarged left-brace 1st Row 1st column negative 0.5 x minus 1, 2nd column x less-than-or-equal-to 0 2nd row 1st column 2 x minus 2, 2nd column x greater-than-or-equal-to 0 EndLayout
Mathematics
2 answers:
aivan3 [116]2 years ago
6 0

Answer:c

Step-by-step explanation:

egoroff_w [7]2 years ago
4 0

Answer:

It was actually A on edgen.  

Step-by-step explanation:

Guest
1 year ago
CORRECT!
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a university theater sold 556 tickets for a play, tickets cost $22 per adult tickets and $ 12 for senior citizen ticket, if the
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2 years ago
Monifer used substitution to solve this system of equations. Which equation could be the result of her first step? 3a +b=225 b=a
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8 0
2 years ago
In a GP if T3 = 18 and T6 = 486 Find:- T10
mote1985 [20]

Answer:

The 10th term of the G.P is 29.              

Step-by-step explanation:

Given : In a GP if T_3=18 and T_6 = 486.

To find : The term T_{10} ?

Solution :

The geometric sequence is in the form, a,ar,ar^2,ar^3,...

Where, a is the first term and r is the common ratio.

The nth term of G.P is T_n=ar^{n-1}

We have given, T_3=18

i.e. T_3=ar^{3-1}

18=ar^{2} ....(1)

T_6 = 486

i.e. a_6=ar^{6-1}

486=ar^{5} ....(2)

Solving (1) and (2) by dividing them,

\frac{486}{18}=\frac{ar^{5}}{ar^{2}}

27=r^3

r=\sqrt[3]{27}

r=3

Substitute in (1),

18=a(3)^{2}

18=9a

a=2

The first term is a=2 and the common ratio is r=3.

The 10th term, of GP is given by,

T_{10}=2+(10-1)3

T_{10}=2+(9)3

T_{10}=2+27

T_{10}=29

Therefore, The 10th term of the G.P is 29.

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