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Svetradugi [14.3K]
1 year ago
7

Solve and simplify: x(x - 1) = 121 – x​

Mathematics
2 answers:
vaieri [72.5K]1 year ago
4 0

Answer:

\boxed{\bold{x  \ =  \ 11  \ or  \ x  \ =  \ -11}}

Explanation:

\bold{x(x  \ -  \ 1)  \ =  \ 121  \ -  \ x}

Simplify both sides of the equation

x² − x = −x + 121

Add x to both sides

x² − x + x = −x + 121 + x

x² = 121

Take square root

x = ± √121

x = 11 or x = −11

GuDViN [60]1 year ago
3 0

Answer:

x=11

Step-by-step explanation:

x(x-1)=121-x\\\\x^2-x=121-x\\\\x^2=121\\\\x=\sqrt{121}\\\\x=11

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Answer:

(1) Correct option (A).

(2) The probability that Aadi will get Tails is 0.40.

Step-by-step explanation:

The information provided is:

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  • Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

P(T|E)=\frac{3}{10}=0.30

P(T|S)=\frac{20}{50}=0.40

Here,

P (T|E) implies the probability of tail in case of Eric's experiment.

P (T|S) implies the probability of tail in case of Sue's experiment.

(1)

Now, it is given that Aadi is going to throw the coin once.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the probability of Aadi getting Tails in a single toss.

As Sue uses a larger number of trials in the experiment, i.e. n = 50 > 30 times, according to the Central limit theorem, Sue's estimate is best because she throws it .

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As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

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