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bezimeni [28]
2 years ago
13

A frozen dinner at a grocery store is purchased for $2.20 wholesale and is marked up by 40 percent. A customer wants to buy four

frozen dinners. How much will the customer pay, including paying 9 percent sales tax? Round your answer to the nearest cent.
Mathematics
2 answers:
Y_Kistochka [10]2 years ago
8 0
Since the frozen dinner at the grocery store was bumped up by 40%, the new price would have been $3.08
Now, a customer wants to buy 4 frozen dinners, so multiply the price of one frozen dinner by 4.
$3.08 x 4 = $12.32
There is a 9% sales tax put up for the grocery store. You will want to multiply 9% (or .09) times the price of the 4 frozen dinners.
$12.32 x .09 ~ $1.11
Add the sales tax price to the price of the four frozen dinners.
$12.32 + $1.11 = $13.43 
$13.43 will be the amount the customer will pay.
sergeinik [125]2 years ago
8 0

Answer:

13.43 is the answer

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There are 30 businesses with 4 executives each for the new office building. Each business needs one office for each of its
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B

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Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data
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Answer:

The correct options are;

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A

Step-by-step explanation:

Here we have for City A

Maximum - Minimum = 10

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City B

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Interquartile range =9.5

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.

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Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif
Nadusha1986 [10]

Answer:

sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

Step-by-step explanation:

given is the Differential equation in I order linear as

y′+4y=48t,y(0)=9.

Take Laplace on both sides

L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}

Now if we take inverse we get y(t) the solution

Thus the algebraic equation would besY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

8 0
2 years ago
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