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2 years ago

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A worker is paid rs. 2130 for 6 days .if his total wage during a month is rs. 9230 find the number of days he worked in the mont

h ..

1 answer:

Katyanochek1 [597]2 years ago

4 0

Answer:

26 days

Step-by-step explanation:

If 6 days = rs. 2130

then 1 day = (2130 × 1) ÷ 6

Therefore 1 day = rs 355

For rs. 9230, the number of days he worked:

= 9230 ÷ 355

= 26 days

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An entrepreneur estimates his total profit (total revenue minus total cost) for his proposed company as p(x) = x3 − 4x2 + 5x − 2

RideAnS [48]

Answer:

Year in which the entrepreneur break even is 4

Step-by-step explanation:

We are given:

p(x) = x^3-4x^2+5x-20

We would find the value of x

Solving:

x^3-4x^2+5x-20 = 0

(x^3-4x^2)+(5x-20) = 0

x^2(x-4)+5(x-4) = 0

(x-4)(x^2+5)=0

=> x-4 = 0 and x^2+5 =0

x = 4 and x^2 = -5

x = 4 and x = ±√-5 or ±√5 i (not real solutions)

So, x = 4

So, year in which the entrepreneur break even is 4

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2 years ago

Find the volume of a cube if an edge has length 4xyz units

Monica [59]

The volume of a cube is found by multiplying the length of any edge by itself twice. So if the length of an edge is 4, <span>the volume is 4 x 4 x 4 = 64</span>

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2 years ago

Read 2 more answers

Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week. With a full tank

timama [110]

Answer:

50 miles.

Step-by-step explanation:

Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.

With a full tank of gas he can drive 100 miles.

Question asked:

How many miles can he drive on the weekend, before he he fills up again?

Solution:

With full tank he can drive a total distance = 100 miles

Each day of the work week, he drives = 10 miles

Total miles, he drive in whole work week (Monday - Friday) = $10\times5=50\ miles$

<em>Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-</em>

100 - 50 = 50 miles.

Therefore, he can drive 50 miles on the weekend, before he he fills up again.

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2 years ago

It takes Wayne 1/10 hours to walk a 1/6 mile park loop. What is Wayne's unit rate, in miles per hour

olchik [2.2K]

To solve this problem, we should set up a proportion, letting x represent our unknown number of miles that Wayne walks in one hour.

1/6 mile / 1/10 hours = x miles / 1 hour

Now we use cross-products or the multiplication of the numerator of one fraction times the denominator of the other fraction, setting these two numbers equal. The resulting equation is:

1/6 = 1/10x

Finally, we must divide both sides by 1/10 to cancel it out on the right side of the equation and get the variable x alone.

x = 5/3 or 1 2/3

Therefore, Wayne walks 1 2/3 miles per hour.

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2 years ago

If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.

fenix001 [56]

Given:

$h:k=2:5,x:y=3:4,2h+x:k+2y=1:2$

To find:

$h-x:k-y$

Solution:

We have, $h:k=2:5$ and $x:y=3:4$ .

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

$2h+x:k+2y=1:2$

It can be written as

$\dfrac{2h+x}{k+2y}=\dfrac{1}{2}$

$\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}$

$\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}$

$2(4a+3b)=1(5a+8b)$

On further simplification, we get

$8a+6b=5a+8b$

$8a-5a=8b-6b$

$3a=2b$

$a=\dfrac{2b}{3}$

Now,

$h-x:k-y=\dfrac{h-x}{k-y}$

$h-x:k-y=\dfrac{2-3b}{5a-4b}$

$h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}$

$h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}$

On further simplification, we get

$h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}$

$h-x:k-y=\dfrac{-5b}{-2b}$

$h-x:k-y=\dfrac{5}{2}$

$h-x:k-y=5:2$

Therefore, the ratio $h-x:k-y$ is $5:2$ .

8 0

1 year ago