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ser-zykov [4K]
1 year ago
9

The figure below shows the dimensions of a city park in feet. Shannon thinks the area of city park is 73,084 square feet. Do you

agree or disagree with her? Justify your answer by finding the area of city park. Explain how you solved this problem.

Mathematics
1 answer:
Andreyy891 year ago
3 0

Answer:

We need to solve for the 4th side

4th side base = 75.5 -60.5 = 10 feet

4th side height = 16

4th side LENGTH^2 = 10^2 + 16^2

4th side = sq root (356) = 18.8679622641

Trapezoid Area = [(sum of the bases) / 2 ] * height

Trapezoid Area = [(136)/2] * 16

Trapezoid Area = 1,088 square feet, which is MUCH smaller

than 73,084

Step-by-step explanation:

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Sedaia [141]
1. lines j and k because they have the same slope.
2.d because -1/3 is the opposite slope of 3 and it passes through that point.
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Cuando un oso grizzly hiberna, su ritmo cardiaco disminuye a 101010 latidos por minuto, que es 20\%20%20, percent de su valor no
zheka24 [161]

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La frecuencia cardíaca normal de un oso pardo cuando no está hibernando es de 50 latidos por minuto.

Step-by-step explanation:

5 0
1 year ago
Given a real number x and a positive integer k, determine the number of multiplications used to find x2k starting with x and suc
Alex

Answer: It is a more efficient way to find x2k than by multiplying x by itself the appropriate number of times.

Step-by-step explanation: Please find the attached file for the solution

8 0
1 year ago
Shelter A has a capacity of 300 beds and is 80% occupied. Shelter B is 45% occupied. The ratio of the occupancy of shelter A to
sasho [114]

Answer:there are 900 beds in shelter B

Step-by-step explanation:

Shelter A has a capacity of 300 beds and is 80% occupied. This means that the number of beds in Shelter A that would be

80/100 × 300 = 0.8 × 300 = 240 beds.

Let x represent the capacity of Shelter B. Shelter B is 45% occupied. It means that number of beds in Shelter B that would be occupied is

45/100 × x = 0.45 × x = 0.45x beds.

Total occupancy of shelter A and shelter B would be

240 + 0.45x

The ratio of the occupancy of shelter A to shelter B is 16:27

Total ratio of occupancy = 16 + 27 = 43

Therefore

27/43 × (240 + 0.45x) = 0.45x

27(240 + 0.45x) = 0.45x × 43 = 19.35x

6480 + 12.15x = 19.35x

6480 = 19.35x - 12.15x = 7.2x

x = 6480/7.2 = 900

3 0
1 year ago
A real estate company is interested in testing whether the mean time that families in Gotham have been living in their current h
djverab [1.8K]

Answer:

Correct option: a. The null hypothesis is rejected.

Step-by-step explanation:

A statistical hypothesis test for difference between two means can be used to determine whether the mean time that families in Gotham have been living in their current homes is less than families in Metropolis.

The hypothesis is:

<em>H</em>₀: The mean time that families in Gotham in their current homes is not less than families in Metropolis,i.e. <em>μ</em>₁ ≥ <em>μ</em>₂.

<em>Hₐ</em>: The mean time that families in Gotham in their current homes is less than families in Metropolis,i.e. <em>μ</em>₁ < <em>μ</em>₂.

Given:

\bar X_{G}=35\\\bar X_{M}=50\\S_{G}^{2}=900\\S_{M}^{2}=105\\n_{G}=100\\n_{M}=150

Assuming that the significance level of the test is, <em>α</em> = 0.10.

The test statistic is:

t=\frac{\bar X_{G}-\bar X_{M}}{s_{p}\sqrt{\frac{1}{n_{G}}+\frac{1}{n_{M}}}}

Here s_{p} = pooled standard deviation.

Compute the value of s_{p} as follows:

s_{p} = \sqrt{\frac{(n_{G}-1)S_{G}^{2}+(n_{M}-1)S_{M}^{2}}{n_{G}+n_{M}-2}}=\sqrt{\frac{(100-1)900+(150-1)105}{100+150-2}}=20.55

Compute the test statistic value as follows:

t=\frac{\bar X_{G}-\bar X_{M}}{s_{p}\sqrt{\frac{1}{n_{G}}+\frac{1}{n_{M}}}}=\frac{35-50}{20.55\sqrt{\frac{1}{100}+\frac{1}{150}}}=-5.654

The test statistic value is -5.654.

The critical value of the test is, t_{\alpha, (n_{G}+n_{M}-2)}=t_{0.10,(100+150-2)}=t_{0.10,248}=-1.282

*Use a <em>t</em>-table for the value.

*The negative sign is because of the test is left-tailed.

*Since the table does not consist the value for the degrees of freedom 248 use the next highest value.

Decision rule:

If the test statistic value is less than the critical value then the null hypothesis is rejected.

Test statistic = -5.654 < Critical <em>t</em> = -1.282.

Thus, the null hypothesis is rejected.

8 0
1 year ago
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