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allochka39001 [22]
2 years ago
5

A pound of oranges costs $2 less than a pound of pears. Together, ten pounds of oranges and eight pounds of pears cost $61. How

much would three pounds of pears cost?
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
3 0

Let us say that:

o = cost of oranges per pound

p = cost of pears per pound

 

so that:

o = p – 2

 

Therefore:

10o + 8p = 61

10 (p – 2) + 8p = 61

10p – 20 + 8p = 61

18p = 81

p = 4.5

p = $4.5 per pound

 

So 3 pounds of pears would cost:

total cost = 3 * 4.5

total cost = $13.5

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faltersainse [42]

Answer:

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

24x+6 is equivalent to 6(4x+1) and (6*4x)+(6*1)

(4*6x)+(4*2) is equivalent to 24x+8 and 4(6x+2)

Step-by-step explanation:

An equivalent expression is an expression which either simplified or factored is equal to it.

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

24x+6 is equivalent to 6(4x+1) and (6*4x)+(6*1)

(4*6x)+(4*2) is equivalent to 24x+8 and 4(6x+2)

5 0
2 years ago
A food company originally sells cereal in boxes with dimensions 25 cm by 14 cm by 10 cm. To make more profit, the company decrea
hjlf

Answer:

1.75 cm

Step-by-step explanation:

We are given that the dimensions of the box as 25 cm by 14 cm by 10 cm.

Now, to increase the profit, the dimensions of the box by 'x' cm.

Thus, the new dimensions are (25-x) cm by (14-x) cm by (10-x) cm.

Further, it is given that the volume of the new box is 2,208 cm^{3}

As, Volume of the box = Length × Breadth × Height

i.e. 2208 = (25-x) × (14-x) × (10-x)

i.e. 2208 = (25-x) \times (140-24x-x^{2})

i.e. 2208=x^{3}-x^{2}-740x+3500

i.e. x^{3}-x^{2}-740x+1292=0

On solving this cubic equations, we get that, the solutions are x = 27.6, x = 1.75 and x = 26.8.

Since, the dimensions 25 cm by 14 cm by 10 cm are reduced by x cm.

Thus, if x = 27.6 or x = 26.8, then (10-x) = -17.6 or -16.8, which cannot be possible. So, x = 1.75 cm.

Hence, the dimensions were decreased by 1.75 cm.

3 0
2 years ago
Which two values of x are roots of the polynomial below?<br> 4x2-6x+1
viva [34]

Answer:

4x2-6x+1

∆=√-6^2-4×1×4

∆=√36-16=√20

∆=2√5

root1=(6+√20)/8

root2=(6-√20)/8

6 0
2 years ago
A bug is moving back and forth on a straight path. The velocity of the bug is given by vt=t2-3t. Find the average acceleration o
g100num [7]

Answer:

2 unit/time²

Step-by-step explanation:

Given the equation:

v(t) =t^2-3t

At interval ; 1, 4

V(1) = 1^2 - 3(1)

V(1) = 1 - 3

V(1) = - 2

At t = 4

V(4) = 4^2 - 3(4)

V(4) = 16 - 12

V(4) = 4

Average acceleration : (final - Initial Velocity) / change in time

Average acceleration = (4 - (-2)) ÷ (4 - 1)

Average acceleration = (4 + 2) / 3

Average acceleration = 6 /3

Average acceleration = 2

3 0
2 years ago
Estimate 1/5 percent of 201
mote1985 [20]
If you would like to estimate 1/5 percent of 201, you can calculate this using the following steps:

1/5 percent of 201 = 1/5% of 201 = 1/5% * 201 = 1/5 / 100 * 201 = 1/500 * 201 = 201/500 = 0.402

Result: 1/5 percent of 201 is 0.402.
7 0
2 years ago
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