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UNO [17]
2 years ago
11

A sum of money when invested for a definite period at r% simple interest will yield an interest of rm80 .using the same interest

rate, find the interest earned if the sum is tripled and the investment period is doubled
Mathematics
1 answer:
maks197457 [2]2 years ago
7 0
The invest could probably be maybe 8% for a question
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Consider the following sets. U = {ordered pairs on a coordinate plane} A = {ordered pair solutions to y = x} B = {ordered pair s
4vir4ik [10]

Answer:

(0,0)

Step-by-step explanation:

We have,

U = { (x,y) : x,y belong to real numbers }

A = { (x,y) : (x,y) is a solution of y=x }

B = { (x,y) : (x,y) is a solution of y=2x }

We need to find the ordered pair (x,y) that belong to A\bigcapB.

Let, (x,y) belong to A\bigcapB

i.e. (x,y) belong to A and (x,y) belong to B

i.e. y = x and y = 2x

i.e. x = 2x

i.e. x = 0

Now, substitute x= 0 in any of the equation say y = x, we get y = 0.

Hence, the ordered pair satisfying A\bigcapB is (0,0).

5 0
2 years ago
Read 2 more answers
In 2011, a train carried 8% more passengers than in 2010. In 2012 , it carried 8% more passengers than in 2011. Find the percent
konstantin123 [22]

Answer:

there was a 16% increase since 2010 to 2012

Step-by-step explanation:

lets say the train had 100 people on it in 2010 and in 2011 it had an 8% increase which then brings you to 8 plus 100 and you get 108.

Now in 2012 there was an increase 8%, so you will add 8 to your previous answer 108 and receive 116. So now there was 16 more passengers in 2012 than in 2010. Transfer the 16 passengers into 16% and you now have your answer.

5 0
2 years ago
Jackson travels 2 km north, then 3 km east, and finally 2 km south. Which
jonny [76]
D none of the above
Jackson is 3 km east of where he started
8 0
2 years ago
Evaluate the line integral by the two following methods. xy dx + x2y3 dy C is counterclockwise around the triangle with vertices
nadezda [96]

Answer:

a)

\frac{2}{3}

b)

\frac{2}{3}

Step-by-step explanation:

a) The first part requires that we use line integral to evaluate directly.

The line integral is

\int_C xydx +  {x}^{2}  {y}^{3} dy

where C is counterclockwise around the triangle with vertices (0, 0), (1, 0), and (1, 2)

The boundary of integration is shown in the attachment.

Our first line integral is

L_1 = \int_ {(0,0)}^{(1,0)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is y=0, x varies from 0 to 1.

When we substitute y=0 every becomes zero.

\therefore \: L_1 =0

Our second line integral is

L_2 = \int_ {(1,0)}^{(1,2)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is:

x = 0 \implies \: dx = 0

y varies from 1 to 2.

We substitute the boundary and the values to get:

L_2 = \int_ {1}^{2}1 \cdot y(0) +  {1}^{2}   \cdot \: {y}^{3} dy

L_2 = \int_ {1}^2 {y}^{3} dy =  \frac{8}{3}

The 3rd line integral is:

L_3 = \int_ {(1,2)}^{(0,0)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is

y = 2x \implies \: dy = 2dx

x varies from 0 to 1.

We substitute to get:

L_3 = \int_ {1}^{0} x \cdot \: 2xdx +  {x}^{2}  {(2x)}^{3}(2 dx)

L_3 = \int_ {1}^{0} 8 {x}^{5}  + 2 {x}^{2} dx  =  - 2

The value of the line integral is

L = L_1 + L_2 + L_3

L = 0 +  \frac{8}{3}  +  - 2 =  \frac{2}{3}

b) The second part requires the use of Green's Theorem to evaluate:

\int_C xydx +  {x}^{2}  {y}^{3} dy

Since C is a closed curve with counterclockwise orientation, we can apply the Green's Theorem.

This is given by:

\int_C \: Pdx +Q  \: dy =  \int \int_ R \: Q_y -  P_x \: dA

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int \int_ R \: 3 {x}^{2}  {y}^{2}  -  y \: dA

We choose our region of integration parallel to the y-axis.

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \int_ 0^{2x}  \: 3 {x}^{2}  {y}^{2}  -  y \: dydx

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \:  {x}^{2}  {y}^{3}  -   \frac{1}{2}  {y}^{2} |_ 0^{2x}  dx

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \:  8{x}^{5} -  2 {x}^{2}   dx =  \frac{2}{3}

8 0
2 years ago
Two busses leave Billings at the same time. The Seattle bus heads west on I-90 at a speed of 73 miles per hour while the Chicago
eimsori [14]

Answer:

  3.5 hours

Step-by-step explanation:

The buses are separating from each other at a speed of 73+79 = 152 miles per hour. Since time = distance/speed, the time it takes to be 532 miles apart is ...

  time = (532 miles)/(152 miles/hour) = (532/152) hours = 3.5 hours

7 0
2 years ago
Read 2 more answers
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