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Korvikt [17]
2 years ago
10

Santa and his elves had a workshop that allowed them to produce 2 2 , 9 1 2 , 5 4 6 , 9 9 2 toys each year. The world population

increased, so they built a new workshop. The new workshop allows them to produce 4 , 1 3 4 , 2 3 2 , 6 3 8 , 9 3 7 toys each year. Approximately how many times as many toys can the new workshop produce each year compared to the old workshop?
Mathematics
2 answers:
denpristay [2]2 years ago
6 0
New Workshop: 4,134,232,638,937
Old Workshop: 22,912,546,992

New/Old = 180.435

The new workshop can produce approximately 180 times as many toys as the old workshop.
Mnenie [13.5K]2 years ago
6 0

Answer:

b 2⋅10e2

Step-by-step explanation:

i had this

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nika2105 [10]
So hmm is a geometric sequence, meaning, the next term is found by multiplying it by "something", namely the "common ratio"

now, if the next term is the product of the common ratio and the previous term, that means, if we divide the previous term by the next term, the quotient will then be the "common ratio", let's do that then

let's divide the 2nd term by the 1st term then

\bf \cfrac{-2x^2-6x}{x+3}\implies \cfrac{-2x\underline{(x+3)}}{\underline{(x+3)}}\implies \boxed{-2x}\impliedby \textit{common ratio}\\\\
-----------------------------\\\\

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{value of first term}\\
r=\textit{common ratio}\\
----------\\
a_1=x+3\\
n=8\\
r=-2x
\end{cases}
\\\\\\
a_8=(x+3)(-2x)^{8-1}\implies a_8=(x+3)(-2x)^7
\\\\\\
a_8=(x+3)(-2^7x^7)\implies a_8=(x+3)(-128x^7)
\\\\\\
a_8=-128x^8-384x^7
8 0
2 years ago
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Answer:

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Step-by-step explanation:

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Hello!

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