How much Greater is the amount Jason paid than amount he charged

Recent studies indicate that the typical 50-year-old woman spends $350 per year for personal-care products. The distribution of

jek_recluse [69]

Answer:

P ( x_bar > 335 ) = 0.9826

Step-by-step explanation:

Given:

- Mean amount u = 350

- standard deviation s.d = 45/year

- Sample size n = 40

Find:

- The probability of sample mean P( x_bar > 335 )

Solution:

- P ( x_bar > 335 ) = P ( Z > sqrt(n)*(x_bar - u)/s.d)

= P ( Z > sqrt(40)*(335-350)/45)

= P ( Z > -2.111) = P ( Z < 2.111)

= 0.5 + P( 0 < Z < 2.111)

= 0.5 + 0.4826

= 0.9826

4 0

2 years ago

Each base of a cylinder has an area of 1,962.5 square centimeters. The cylinder's lateral area is 194.2 square centimeters. Find

Law Incorporation [45]

Total surface area of the cylinder= 2*area of base+lateral area=
=2*1962.5 + 194.2 = 4119.2 cm²

1m=100 cm
1m² = (100 cm)²
1m²=10000cm²

4119.2 cm² *(1m²/10000 cm²)= 0.41192 m²

7 0

2 years ago

Tom and jerry have to stuff and seal 63 envelopes for a new marketing campaign. Jerry can stuff and seal 15 envelopes alone in 2

zheka24 [161]

Chile—. Ion understand, good luck tho.....

7 0

2 years ago

1. Three friends pooled their money to purchase a new game system that costs $298. One person

iragen [17]

Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → $f+s+t=298$

Equation 2 → $s=f-9$

Equation 3 → $t=f-14$

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

$f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107$

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

$s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93$

5 0

2 years ago

a motor boat traveled 18 miles down a river in 2 hours but took 4.5 hours to return upstream. Find the rate of the motor boat in

tangare [24]

Answer:

rate of the boat in still water = 6.5 miles / hour

rate of the current = 2.5 miles / hour.

Explanation:

1) Name the two variables:

c: rate of the current

b: rate of the boat in still water:

With that, the net rates of the boat down the river and upstrean are:

down the river: b + c

upstream: b - c

2) Now set the equations for the distance as a function of the times and the rates:

distance = rate × time

downstream: 18 miles = (b + c) × 2 hours

upstream: 18 miles = (b - c) × 4.5 hours

3) Set the system of equations:

18 = 2(b + c) ⇒ 9 = b + c . . . Equation (1)

18 = 4.5 (b - c) ⇒ 4 = b - c . . . Equation (2)

4) Solve the system by elimination:

Add equations (1) and (2): 9 + 4 = 2b

Divide both sides by 2: 13/2 = b

Simplify: b = 6.5

Replace b with 6.5 in equation (2) and solve:

4 = 6.5 - c ⇒ c = 6.5 - 4 = 2.5

5) Results:

b = rate of the boat in still water = 6.5 miles / hour

c = rate of the current = 2.5 miles / hour.

3 0

2 years ago

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