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2 years ago

Two groups of students were asked how many pets they had. The table below shows the numbers for each group:

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

where are the answers?

VLD [36.1K]2 years ago

4 0

Answer:

The Answer choices are this below

The interquartile range for Group A students is 0.5 less than the interquartile range for Group B students.

The interquartile range for Group A students is 1.5 more than the interquartile range for Group B students.

The interquartile range for Group A students is equal to the interquartile range for Group B students.

The interquartile range for Group A students is 1 more than the interquartile range for Group B students.

Step-by-step explanation:

The answer is d because it has a wider range than company b but i could be wrong this kind of math is not my specialty.

Guest

1 year ago

thank you so much

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Suppose that we wish to expand (x + y + z)17. what is the coefficient of x 2 y5z10

Delvig [45]

We use the trinomial theorem to answer this question. Suppose we have a trinomial (a + b + c)ⁿ, we can determine any term to be:

[n!/(n-m)!(m-k)!k!] a^(n-m) b^(m-k) c^k

In this problem, the variables are: x=a, y=b and z=c. We already know the exponents of the variables. So, we equate this with the form of the trinomial theorem.

n - m = 2
m - k = 5
k = 10

Since we know k, we can determine m. Once we know m, we can determine n. Then, we can finally solve for the coefficient.

m - 10 = 5
m = 15

n - 15 = 2
n = 17

Therefore, the coefficient is equal to:

Coefficient = n!/(n-m)!(m-k)!k! = 17!/(17-5)!(15-10)!10! = 408,408

6 0

2 years ago

City planners are creating a 3-dimensional model of a city park to find the best placement for a new tennis court. The city park

inn [45]

First, divide the original measurements with the scaled ones. You'll get the same answer meaning that is the scale used by the model.
1500 ft. ÷7.5 ft = 200
600 ft. ÷ 3 ft. = 200

To simply check, if you divide 1500 with 200, the answer is 7.5 and 600 divided by 200 is 3.
To find the scaled dimension of the tennis court with actual dimension of 120 ft by 60 ft, divide both values with the scale used in the model which is 200.

120 ft. ÷ 200 = 0.6 ft
60 ft. ÷ 200 = 0.3 ft

The dimension of the tennis court in the scaled model is 0.6 ft long and 0.3 ft. wide.

8 0

2 years ago

At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least

evablogger [386]

We can let r be the number of food tickets and f be the number of food tickets. Since Alana can spend at most $40, that means the total of price bought for r and f must be less than or equal to $40. In addition, since Alana buys at least 16 tickets, this also means that the total of r and f is 16. Mathematically, we have these inequalities: (1) 4r + 2f ≤ 40 and (2) r + f ≥ 16 Multiplying -2 in (2), we have 4r + 2f ≤ 40 -2r - 2f ≤ 32 Adding both inequalities, 2r ≤ 8 r ≤ 4 Since r must be less than or equal to 4.Thus the answer is A.

5 0

2 years ago

Read 2 more answers

Which graph represents the function f(x) = (x – 5)2 + 3?

goblinko [34]

The function
$f(x)=(x-5)^2+3$
describes a parabola with vertex = (5, 3).

The graph of the function is attached.

4 0

2 years ago

Read 2 more answers

Your band is one of 8 bands competing at the battle of the bands. The order of the performances is determined at random. The fir

lorasvet [3.4K]

Answer:

1.79 %.

Step-by-step explanation:

you have to calculate the probability of a series of events before you can calculate the final probability.

The first event is that the band plays on Friday.

If there are 8 bands, but only 5 play on Friday, then the probability that they will play on Friday is

5/8

Now, the second event that they are the last ones is 1/5, since they are 5 bands.

Therefore the probability that they will play on Saturday and last is

5/8 * 1/5 = 1/8

Now, for the rival band it would be, knowing that on Friday there is already a quota assigned and one band less, the probability that they will play that day is

4/7

as they play before the other group, it would be 1/4, as there is already a quota assigned.

The final probability would then be:

4/7 * 1/4 = 1/7

Now the probability that the band gives the last performance on Friday night and your rival band performs immediately before them, is:

1/8 * 1/7 = 0.0179

That is 1.79 %.

3 0

2 years ago