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2 years ago

Two groups of students were asked how many pets they had. The table below shows the numbers for each group:

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

where are the answers?

VLD [36.1K]2 years ago

4 0

Answer:

The Answer choices are this below

The interquartile range for Group A students is 0.5 less than the interquartile range for Group B students.

The interquartile range for Group A students is 1.5 more than the interquartile range for Group B students.

The interquartile range for Group A students is equal to the interquartile range for Group B students.

The interquartile range for Group A students is 1 more than the interquartile range for Group B students.

Step-by-step explanation:

The answer is d because it has a wider range than company b but i could be wrong this kind of math is not my specialty.

Guest

1 year ago

thank you so much

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Jala put $600 in an interest bearing account with a annual compound interest rate of 5%. Jala determined that after seven years,

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Answer:

7.4 years would be the correct answer

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2 years ago

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A set of data has a mean of 56.1. The data follows a normal distribution curve and has a standard deviation of 8.2. Find the pro

Whitepunk [10]

Given that mean=56.1 and standard deviation=8.2, P(x>67.5) will be found as follows:
The z-score is given by:
z=(x-μ)/σ
thus the z-score will be given by:
z=(67.5-56.1)/8.2
z=11.4/8.2
z=1.39
thus
P(z=1.39)=0.9177
thus:
P(x>67.5)=1-P(z>0.9177)
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7 0

1 year ago

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Find three different surfaces that contain the curve r(t) = t^2 i + lnt j + (1/t)k

Viefleur [7K]

solution:

Consider the curve: r(t) = t²i +(int)j + 1/t k

X= t² , y = int ,z = 1/t

Using, x = t², z = 1/t

X = (1/z)²

Xz²= 1

Using y = int, z= 1/t

Y = in│1/z│

Using x = t², y = int

Y = int

= in(√x)

Hence , the required surface are,

Xz² = 1

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2 years ago

11/12−6/1q+6/5q−3/1, Combine like terms to create an equivalent expression.

Nikolay [14]

Answer: $-\frac{25}{12} -\frac{24q}{5}$

Step-by-step explanation:

$\frac{11}{12} -\frac{6}{1} q+\frac{6}{5}q-\frac{3}{1}$

$\frac{11}{12} -6q+ \frac{6q}{5} -\frac{3}{1}$

$\frac{11}{12}-6q \frac{6q}{5} -3$

$(\frac{11}{12} -3)+(-6q+\frac{6q}{5} )$

$-\frac{25}{12}- \frac{24q}{5}$

Simplify three times, collect like terms and simplify again, how to collect like terms see their differences and then put them into groups, for example I put all the numbers without variables on one side and all the numbers with variables on another.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

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2 years ago

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A box of chocolates contains five milk chocolates, three dark chocolates, and four white chocolates. You randomly select and eat

PolarNik [594]

Answer:

60/220

Step-by-step explanation:

we use combination,

$(\frac{5}{1} ) \times ( \frac{4}{1} ) \times ( \frac{3}{1} )$