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2 years ago

Two groups of students were asked how many pets they had. The table below shows the numbers for each group:

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

where are the answers?

VLD [36.1K]2 years ago

4 0

Answer:

The Answer choices are this below

The interquartile range for Group A students is 0.5 less than the interquartile range for Group B students.

The interquartile range for Group A students is 1.5 more than the interquartile range for Group B students.

The interquartile range for Group A students is equal to the interquartile range for Group B students.

The interquartile range for Group A students is 1 more than the interquartile range for Group B students.

Step-by-step explanation:

The answer is d because it has a wider range than company b but i could be wrong this kind of math is not my specialty.

Guest

1 year ago

thank you so much

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Before any dinner service, the manager confirms when the number of reservations at a restaurant is subtracted from twice the num

pochemuha

Answer:

Its A

Step-by-step explanation:

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2 years ago

Compare and contrast expanding and simplifying algebraic expressions with simplifying numeric expressions. For example, compare

larisa [96]

With algebraic expressions, you can’t add and subtract any terms like you can add and subtract numbers. Terms must be like terms in order to combine them. So, you can’t always simplify an algebraic expression by following the order of operations. You have to use the distributive property to rewrite the expression and then combine like terms to simplify. With numeric expressions, you can either simplify inside the parentheses first or use the distributive property first.

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2 years ago

Read 2 more answers

State, with an explanation, whether the mean, median, or mode gives the best description of the following average. The average

erma4kov [3.2K]

Answer:

The mean is the better method.

Step-by-step explanation:

The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.

The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.

As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.

8 0

1 year ago

calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-

Tatiana [17]

Answer:

1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10

Step-by-step explanation:

We can use the distance formula to calculate the lengths of the line segments.

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

1. A (1,5), B (4,5) (red)

$d = \sqrt{(x_{2} - x_{1}^{2}) + (y_{2} - y_{1})^{2}} = \sqrt{(4 - 1)^{2} + (5 - 5)^{2}}\\= \sqrt{3^{2} + 0^{2}} = \sqrt{9 + 0} = \sqrt{9} = \mathbf{3}$

2. A (2,-5), B (2,7) (blue)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(2 - 2)^{2} + (7 - (-5))^{2}}\\= \sqrt{0^{2} + 12^{2}} = \sqrt{0 + 144} = \sqrt{144} = \mathbf{12}$

3. A (3,1), B (-1,4 ) (green)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-1 - 3)^{2} + (4 - 1)^{2}}\\= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = \mathbf{5}$

4. A (-2,-5), B (3,7) (orange)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 - (-2))^{2} + (7 - (-5))^{2}}\\= \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = \mathbf{13}$

5. A (5,4), B (-3,-2) (purple)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-3 - 5)^{2} + (-2 - 4)^{2}}\\= \sqrt{(-8)^{2} + (-6)^{2}} = \sqrt{64 + 36} = \sqrt{100} = \mathbf{10}$

6. A (1,-8), B (-5,0) (black)

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-5 - 1)^{2} + (0 - (-8))^{2}}\\-= \sqrt{(-6)^{2} + (-8)^{2}} = \sqrt{36 + 64} = \sqrt{100} = \mathbf{10}$

6 0

2 years ago

In 2010, Rafik bought a house. In 2015, Rafik sold the house to Bianca. He made a 20% profit on the sale. In 2019, Bianca sold t

sweet [91]

Answer:

£170000

Step-by-step explanation:

In 2010, Rafik bought a house. Let us assume Rafik bought the house for $x. In 2015, Rafik sold the house to Bianca and made 20% profit. 20% profit = 20% of x = 0.2 × x = 0.2x. Therefore Rafik sold the house to Bianca at x + 0.2x = 1.2x. Bianca bought the house at 1.2x

The house was sold by Bianca at 5% loss in 2019. 5% loss = 0.05(1.2x) = 0.06x

Therefore the house was sold by Bianca at 1.2x - 0.06x = 1.14x. Since Bianca sold the house at £193800.

⇒ 1.14x = 193800

x = 193800/1.14

x = £170000

Rafik paid £170000 for the house in 2010

7 0

2 years ago