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Cloud [144]
2 years ago
11

Which inequality statement best describes the probability of event (P) ?

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
6 0

Answer:

0\le P\le 1

Step-by-step explanation:

The probability of an event is a number describing the chance that the event will happen.

Definition: The probability of an evant is

P=\dfrac{\text{Number of favorable outcomes}}{\text{Number of all possible outcomes}}

1. An event that is certain to happen (Number of favorable outcomes = Number of all possible outcomes) has a probability of 1.

2. An event that cannot possibly happen (Number of favorable outcomes = 0) has a probability of 0.

3. If there is a chance that an event will happen, then its probability is between 0 and 1.

Thus,

0\le P\le 1

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An office worker can type at the rate of 57 words per minute. Which equation could be used to solve for the number of words he c
8_murik_8 [283]
57x6 =342
57=per min 
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4 0
2 years ago
Read 2 more answers
Find the volume of the wedge cut from the first octant by the cylinder z=12-3y^2 and the plane x+y=2.
LuckyWell [14K]

Answer:

The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2  

0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2  

V = ∫∫∫ dzdydx  

dz has changed from zero to 12−3y^2  

dy has changed from zero to 2-x  

dx has changed from zero to 2  

V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =  

24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20

Step-by-step explanation:

8 0
2 years ago
A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km and then stops for a 90.0-min na
Oxana [17]

Answer:

(a) 2.29 km/h

(b) 9 km/h

Step-by-step explanation:

For part (a) you have to apply<em> the average speed formula</em>, which is defined by:

v=\frac{d}{t}

where d is the total distance traveled and t is the total time needed.

d=\frac{4.00}{1.75}=2.29 km/h

For part (b) you have to calculate the running time (T) , which is the total time of the race minus the nap time:

The nap time in hours is:

90/60 = 1.5 h (because there are 60 minutes in one hour)

The running time is:

T= 1.75 - 1.5 = 0.25 h

Let t1 represent the time before the nap and t2 the time after the nap:

t1+t2 = T

t1+t2 = 0.25

You have to apply the formula d=vt before and after the nap:

-Before the nap, the distance traveled was 0.50 km

0.50 = v1t1

-Afer the nap, the distance traveled was 3.50 km

3.50=v2t2

But v2=2v1 (because after the nap the rabbit runs twice as fast)

You have to solve the system of equations:

t1=0.25-t2 (I)

v1t1=0.50 (II)

2v1t2=3.50 (III)

Replacing (I) in (II)

v1(0.25-t2)=0.50

Applying distributive property and solving:

0.25v1-v1t2=.050

For (III) you have that v1t2=3.50/2=1.75. Hence:

0.25v1-1.75=0.50

Solving for v1:

v1 = 9 km/h

7 0
1 year ago
which shape had a larger area: a rectangle that is 7 inches by 3/4 inch, or a square with side length of 2.5 inches? Show your r
Brums [2.3K]
In order to find the area for a rectangle, you must multiply length times width, which would be 7 x 3/4 which is 5.25. In order to find the area for a square, you do length^2, also know as length x length. Which would be 2.5^2 which is 2.5 x 2.5 which is 6.25. 6.25 is larger than 5.25, so the square has a larger area.
6 0
2 years ago
A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

l=65 ft

h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

V= 1,277.63\pi\ ft^{3}

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}

6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

7) <u>Find the number of lane miles that were covered with salt</u>

8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to 1,277.63\pi\ ft^{3}

1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

7 0
2 years ago
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