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likoan [24]
2 years ago
5

An office worker can type at the rate of 57 words per minute. Which equation could be used to solve for the number of words he c

an type in 6 minutes?
Mathematics
2 answers:
Natasha2012 [34]2 years ago
7 0
Hello there.

Question: <span>An office worker can type at the rate of 57 words per minute. Which equation could be used to solve for the number of words he can type in 6 minutes?

Answer: </span>57 x 6 = 342.
The equation could be:
57 x 6 = x.
He could write 342 words in 6 minutes.

Hope This Helps You!
Good Luck Studying ^-^

8_murik_8 [283]2 years ago
4 0
57x6 =342
57=per min 
6=how many mins
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Students collected data about the capacities of their lungs by inflating balloons with a single breath. they measured the circum
marishachu [46]
The given data is the following:

Student Trial 1  Trial 2 Trial 3 Average
-----------  --------  --------  --------  ------------
    1           66.0    66.5   68.5     67.0
    2          67.5     64.0   70.5     67.3
    3          60.3     60.5   60.5    61.0
    4          55.0     58.0   59.0    57.3

Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0   Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3    Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604    Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3    Correct

Answer: Student 3
6 0
2 years ago
Read 2 more answers
Use green's theorem to compute the area inside the ellipse x252+y2172=1. use the fact that the area can be written as ∬ddxdy=12∫
Pavel [41]

The area of the ellipse E is given by

\displaystyle\iint_E\mathrm dA=\iint_E\mathrm dx\,\mathrm dy

To use Green's theorem, which says

\displaystyle\int_{\partial E}L\,\mathrm dx+M\,\mathrm dy=\iint_E\left(\frac{\partial M}{\partial x}-\frac{\partial L}{\partial y}\right)\,\mathrm dx\,\mathrm dy

(\partial E denotes the boundary of E), we want to find M(x,y) and L(x,y) such that

\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1

and then we would simply compute the line integral. As the hint suggests, we can pick

\begin{cases}M(x,y)=\dfrac x2\\\\L(x,y)=-\dfrac y2\end{cases}\implies\begin{cases}\dfrac{\partial M}{\partial x}=\dfrac12\\\\\dfrac{\partial L}{\partial y}=-\dfrac12\end{cases}\implies\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1

The line integral is then

\displaystyle\frac12\int_{\partial E}-y\,\mathrm dx+x\,\mathrm dy

We parameterize the boundary by

\begin{cases}x(t)=5\cos t\\y(t)=17\sin t\end{cases}

with 0\le t\le2\pi. Then the integral is

\displaystyle\frac12\int_0^{2\pi}(-17\sin t(-5\sin t)+5\cos t(17\cos t))\,\mathrm dt

=\displaystyle\frac{85}2\int_0^{2\pi}\sin^2t+\cos^2t\,\mathrm dt=\frac{85}2\int_0^{2\pi}\mathrm dt=85\pi

###

Notice that x^{2/3}+y^{2/3}=4^{2/3} kind of resembles the equation for a circle with radius 4, x^2+y^2=4^2. We can change coordinates to what you might call "pseudo-polar":

\begin{cases}x(t)=4\cos^3t\\y(t)=4\sin^3t\end{cases}

which gives

x(t)^{2/3}+y(t)^{2/3}=(4\cos^3t)^{2/3}+(4\sin^3t)^{2/3}=4^{2/3}(\cos^2t+\sin^2t)=4^{2/3}

as needed. Then with 0\le t\le2\pi, we compute the area via Green's theorem using the same setup as before:

\displaystyle\iint_E\mathrm dx\,\mathrm dy=\frac12\int_0^{2\pi}(-4\sin^3t(12\cos^2t(-\sin t))+4\cos^3t(12\sin^2t\cos t))\,\mathrm dt

=\displaystyle24\int_0^{2\pi}(\sin^4t\cos^2t+\cos^4t\sin^2t)\,\mathrm dt

=\displaystyle24\int_0^{2\pi}\sin^2t\cos^2t\,\mathrm dt

=\displaystyle6\int_0^{2\pi}(1-\cos2t)(1+\cos2t)\,\mathrm dt

=\displaystyle6\int_0^{2\pi}(1-\cos^22t)\,\mathrm dt

=\displaystyle3\int_0^{2\pi}(1-\cos4t)\,\mathrm dt=6\pi

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2 years ago
Sharon wants to make key chains with different colored beads. Each key chain will look the same. Sharon will use a total of 20 g
skelet666 [1.2K]
20 green and 20 red ?
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2 years ago
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Write a verbal expression for 6m-2
katrin2010 [14]

Answer: The difference of 6 times a number m and 2

Step-by-step explanation:

The way to write this expression is:

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5 0
2 years ago
Suppose 50 percent of the customers at Pizza Palooza order a square pizza, 70 percent order a soft drink, and 35 percent order b
Firdavs [7]

Answer:

Ordering a soft drink is independent of ordering a square pizza.

Step-by-step explanation:

20% more customers order a soft drink than pizza, therefore they cannot be intertwined.

Given: P(A)=0.5 & P(B)=.7

P(A∩B) =  P(A) × P(B)

=  0.5 × .7

=  0.35

P(A∪B) =  P(A) + P(B) - P(A∩B)

=  0.5 + .7 - 0.35

=  0.85

P(AΔB) =  P(A) + P(B) - 2P(A∩B)

=  0.5 + .7 - 2×0.35

=  0.5

P(A') =  1 - P(A)

=  1 - 0.5

=  0.5

P(B') =  1 - P(B)

=  1 - .7

=  0.3

P((A∪B)') =  1 - P(A∪B)

=  1 - 0.85

=  0.15

7 0
1 year ago
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