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Snowcat [4.5K]
2 years ago
12

Students collected data about the capacities of their lungs by inflating balloons with a single breath. they measured the circum

ference of the balloons in centimeters. each student completed three trials and calculated the average. balloon circumference (cm) student trial 1 trial 2 trial 3 average 1 66.0 66.5 68.5 67.0 2 67.5 64.0 70.5 67.3 3 60.3 60.5 60.5 61.0 4 55.0 58.0 59.0 57.3 which student miscalculated her average? 1. student 1 2. student 2 3. student 3 4. student 4
Mathematics
2 answers:
marishachu [46]2 years ago
6 0
The given data is the following:

Student Trial 1  Trial 2 Trial 3 Average
-----------  --------  --------  --------  ------------
    1           66.0    66.5   68.5     67.0
    2          67.5     64.0   70.5     67.3
    3          60.3     60.5   60.5    61.0
    4          55.0     58.0   59.0    57.3

Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0   Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3    Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604    Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3    Correct

Answer: Student 3
tamaranim1 [39]2 years ago
3 0
Look at the given data & calculate the average of each students data,

1) 66, 66.5, 68.5, 67
Average = \frac{66+66.5+68.5}{3} = 67 CORRECT

2) <span>67.5 64.0 70.5 67.3
</span>Average = \frac{67.5+64+70.5}{3} = 67.3 CORRECT

3) <span>60.3 60.5 60.5 61.0
</span>Average = \frac{60.3+60.5+60.5}{3} = 60.43 INCORRECT

4) <span>55.0 58.0 59.0 57.3
</span>Average = \frac{55+58+59}{3} = 57.3 CORRECT



Therefore, 3. Student 3 is the correct answer.

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Answer:

Ruth's 1931 salary was equivalent to a 2015 salary of $1,247,368.

Step-by-step explanation:

This question can be solved by a rule of three.

Government statistics show a consumer price index of 15.2 for 1931 and 237 for 2015.

This means that $15.2 in 1931 is equivalent to $237 in 2015. So

$15.2 in 1931 - $237 in 2015

$80,000 in 1931 - $x in 2015

15.2x = 237*80,000

x = \frac{237*80,000}{15.2}

x = 1,247,368

Ruth's 1931 salary was equivalent to a 2015 salary of $1,247,368.

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2 years ago
What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2Plus or minus 2 StartRoot 5 EndRoot x = ±6Plus or minus 6
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Question:

What are the solution(s) to the quadratic equation 50 – x2 = 0?

A) x = ±2Plus or minus 2 StartRoot 5 EndRoot

B) x = ±6Plus or minus 6 StartRoot 3 EndRoot

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

D) no real solution

Answer:

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

3 0
2 years ago
Read 2 more answers
Focus groups of 15 people are randomly selected to discuss products of the Yummy Company. It is determined that the mean number
Morgarella [4.7K]

Answer:

Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.

Step-by-step explanation:

Consider the provided information.

The mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is 0.58.

Mean = μ= 12.5  

σ = 0.58

n = 15

\mu\pm2\sigma=12.5\pm 2(0.58)\\\mu\pm2\sigma=12.5\pm1.16\\\mu\pm2\sigma=[11.34, 13.66]

Yes, 15 people would be unusual as it falls outside of 2 standard deviation of mean.

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2 years ago
The sales data for January and February of a frozen yogurt shop are approximately normal. The mean daily sales for January was $
VashaNatasha [74]

Answer:

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

Step-by-step explanation:

z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

January:

The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that \mu = 300, \sigma = 20, X = 310. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{310 - 300}{20}

Z = 0.5

February:

The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that \mu = 320, \sigma = 50, X = 340. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{340 - 320}{50}

Z = 0.4

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

3 0
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sattari [20]

Answer:

279 silvery minnow

Step-by-step explanation:

Number of Silvery Minnows initially tagged = 54

Number of minnows captured = 62

Number of tagged minnows in captured ones = 12

Remember that in the very beginning there were no tagged minnows. 54 minnows were captured, tagged and released. This means, there are total 54 tagged minnows in the entire population. Lets say there are x number of minnows in total.

So, in x minnows, 54 are tagged ones.

When 62 minnows are captured, only 12 are tagged ones and remaining are un-tagged. Since, the minnows were randomly captured, we can develop a proportion from this case to estimate the total population of minnows in the Rio Grande River.

Ratio of tagged minnows to total population must be equal to the ratio of captured tagged minnows in total captured minnows.

i.e.

54 : x = 12 : 62\\\\ \frac{54}{x} = \frac{12}{62}\\\\ 62(54)=12x\\ \\ x = 279

This means, there were 279 silvery minnows in the Rio Grande River.

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2 years ago
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