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1 year ago

Find the percent of change from 688 qt to 172 qt.

Mathematics

2 answers:

Sindrei [870]1 year ago

4 0

Answer:

<em>75% decrease.</em>

Step-by-step explanation:

Alekssandra [29.7K]1 year ago

3 0

There is 75% decrease.

Step-by-step explanation:

Given,

Old value = 688 qt

New value = 172 qt

Change = New value - Old value

Change = 172 - 688

Change = -516 qt

The negative sign indicates decrease.

Decrease percent = $\frac{Change}{Old\ value}*100$

Decrease percent = $\frac{516}{688}*100$

Decrease percent = $\frac{51600}{688}$

Decrease percent = 75%

There is 75% decrease.

Keywords: division, subtraction

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2 years ago

An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40

satela [25.4K]

Answer:

0.14 s

Step-by-step explanation:

s = -2.7 t² + 40t + 6.5

Let s = 12

12 = -2.7t² + 40t + 6.5 Subtract 12 from each side

-2.7t² + 40t + 6.5 - 12 = 0

-2.7t² + 40t - 5.5 = 0

Apply the <em>quadratic formula </em>

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = -2.7; b = 40; c = -5.5

$x = \frac{-40\pm\sqrt{40^2 - 4\times (-2.7) \times (-5.5)}} {2(-2.7)}$

$x = \frac{-40\pm\sqrt{1600-59.4}}{-5.4}$

$x = \frac{-40\pm\sqrt{1540.6}}{-5.4}$

$x = \frac{-40\pm 39.25}{-5.4}$

x = 7.41 ± 7.27

x₁ = 0.14; x₂ = 14.68

The graph below shows the roots at x₁ = 0.134 and x₂ = 14.68.

The Moon’s surface is at -12 ft. The ball will be 12 ft above the Moon’s surface (crossing the x-axis) in 0.14 s.

The second root gives the time the ball will be 12 ft above the Moon’s surface on its way back down.

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1 year ago

The mass of an object is equal to the product of the object's density and volume.

AlexFokin [52]

The answer is A you divide 11.3 by 16

6 0

1 year ago

Read 2 more answers

A study found that a driver’s reaction time A(x) to audio stimuli and his or her reaction time V(x) to visual stimuli (both in m

amid [387]

Answer:

The required inequality is $0.0001 x^2 - 0.089 x - 7$ .

Step-by-step explanation:

The given inequalities are

$A(x) = 0.0051x^2 - 0.319x + 15$

$V(x)= 0.005x^2 - 0.23x + 22$

where, x is the driver's age (in years), A(x) is driver’s reaction time to audio stimuli and V(x) is his or her reaction time to visual stimuli, 16 ≤ x ≤ 70.

We need to find an inequality that can be use to find the x-values for which A(x) is less than V(x).

$A(x)$

$0.0051x^2 - 0.319x + 15< 0.005x^2 - 0.23x + 22$

$0.0051x^2 - 0.319x + 15- 0.005x^2 + 0.23x- 22$

Combine like terms.

$0.0001 x^2 - 0.089 x - 7$

where, 16 ≤ x ≤ 70.

Therefore, the required inequality is $0.0001 x^2 - 0.089 x - 7$ .

5 0

2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

4 0

1 year ago