30 x ( 20 / 100 )
= 30 x ( 1 / 5 )
= 30 / 5
= 6
Thank you very much.
Answer:
The 95% confidence interval the average maximum power is (596.0 to 644.0)
Step-by-step explanation:
Average maximum of the sample = x = 620 HP
Standard Deviation = s = 45 HP
Sample size = n = 16
We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.
Degrees of freedom = df = n - 1 = 15
Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table =
= 2.131
The formula to calculate the confidence interval is:

We have all the required values. Substituting them in the above expression, we get:

Thus, the 95% confidence interval the average maximum power is (596.0 to 644.0)
<span>4 x 101^2
------------- = 0.5 x 10^5 = 5 x 10^4
</span><span>8 x 10^7
answer is C.
</span><span>C) 5 x 10</span>^4
To evaluate 17 int (sin^2 (x) cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x)
Cos^3(x) = cosx * (1 - sin^2 (x)) = cosx - cosxsin^2x
So we have 17 int (sin^2x(cosx - cosxsin^2x))
int (sin^2x(cosx)dx - int (sin^4xcosx)dx. ----------(1)
Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]