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IRISSAK [1]
2 years ago
9

Three vertices of a square have coordinates (5, 1), (2, -2), and (-1, 1). What are the coordinates of the fourth vertex?

Mathematics
1 answer:
Tresset [83]2 years ago
6 0
Plot the points
we notice that the square is tilted diagnaol

remember that the legnths of the diagonals of a square are equal


therefor the distance between the points (5,1) and (-1,1) is the same as the ohter diagonal (distance is 6)

the other point is probably that disance up or the y vairable
(2,-2)+6 on the y
-2+6=4
(2,4)
answer is (2,4)
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A set of speakers costs $22 and songs cost $1.25 each. The sales tax rate is 7.5%. The expression 0.075(22 + 1.25s) can be used
kykrilka [37]

Answer:

1.65 + 0.09s

Step-by-step explanation:

Given that :

Cost of speaker = $22

Cost per song = $1.25

Sales tax rate = 7.5%

Expression to obtain the amount of sales tax on entire purchase : 0.075(22 + 1.25s)

Expanding the expression :

0.075(22 + 1.25s)

(0.075 * 22) + (0.075 * 1.25s)

1.65 + 0.09375s

Rounding to the nearest hundredth :

Sales tax on entire purchase :

1.65 + 0.09s

4 0
1 year ago
A liquid dietary product implies in its advertising that use of the product for one month results in an average weight loss of a
BigorU [14]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Please find the table in the attached file.

mean and standard deviation difference: \bar{d}=\frac{\Sigma d}{n} =\frac{-4-6-.......-4-4}{8}=-4.125 \\\\S_d=\sqrt{\frac{\Sigma (d-\bar{d})^2 }{n-1}}=\sqrt{\frac{(-4 + 4.125)^2 +.......+(-4 +4.125)^2 }{8-1}}= 1.246

For point a:

hypotheses are:

H_0 : \mu_d \geq -3\\\\H_a : \mu_d < -3\\\\

degree of freedom:

df=n-1=8-1=7

 From t table, at\alpha = 0.05, reject null hypothesis if t.

test statistic:  

t=\frac{\bar{d}-\mu_d }{\frac{s_d}{\sqrt{d}}}=\frac{ -4.125- (-3)}{\frac{1.246}{ \sqrt{8}}} =-2.55

because the t=-2.553, removing the null assumption. Data promotes a food product manufacturer's assertion with a likelihood of Type 1 error of 0.05.

For point b:

From t table, at \alpha =0.01, removing the null hypothesis if t.

because t=-2.553 >-2.908, fail to removing the null hypothesis.  

The data do not help the foodstuff producer's point with the likelihood of a .01-type mistake.

For point c:

Hypotheses are:

H_0: \mu_d \geq -5\\\\H_a: \mu_d < -5

Degree of freedom:

df=n-1=8-1=7

From t table, at \alpha =0.05, removing the null hypothesis if t.

test statistic:  t=\frac{\bar{d}-\mu_d}{\frac{s_d}{\sqrt{n}}} =\frac{-4.125-(-5)}{\frac{1.246}{\sqrt{8}}}=1.986

Since t-1.986 >-1.895, The null hypothesis fails to reject. The results do not support the packaged food producer's claim with a Type 1 error probability of 0,05.

From t table, at\alpha= 0.01, reject null hypothesis ift.

Since t=1.986>-2.998 , fail to reject null hypothesis.  

Data do not support the claim of the producer of the dietary product with the probability of Type 1 error of .01.

5 0
1 year ago
Alex, Mark &amp; Peter share some money in the ratio 4 : 7 : 1. In total, Alex and Peter receive £60. How much does Mark get?
LuckyWell [14K]

Answer:

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Step-by-step explanation:

7 0
2 years ago
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Rzqust [24]
We know that
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so
the system has an infinite number of solutions

If a consistent system has an infinite number of solutions, it is dependent.
<span>
therefore
the system is </span>consistent, dependent and <span>equivalent
</span><span>
the answer is 
</span>equivalent
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1 year ago
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Natalija [7]
1.50+.25x=3.75
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4 0
2 years ago
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