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scoray [572]
2 years ago
7

Which expression is equivalent to (StartFraction 125 squared Over 125 Superscript four-thirds Baseline EndFraction? StartFractio

n 1 Over 25 EndFraction One-tenth 10 25
Mathematics
1 answer:
stealth61 [152]2 years ago
5 0

Answer:

\frac{125^2}{125^\frac{4}{3}} = 25

Step-by-step explanation:

Given

\frac{125^2}{125^\frac{4}{3}}

Required

Find an equivalent expression

\frac{125^2}{125^\frac{4}{3}}

Apply the following law of indices;

\frac{a^m}{a^n}  a^{m-n}

The expression becomes

125^{2-\frac{4}{3}}

Solve the exponents

125^{\frac{6-4}{3}}

125^{\frac{2}{3}}

Express 125 as 5³

5^{3^*\frac{2}{3}}

Solve the exponents

5^2

25

Hence;

\frac{125^2}{125^\frac{4}{3}} = 25

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The range of all real numbers x such that 2x − 5 < 7 OR 4x + 10 > 6 is___
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First, simplify the two inequalities.

2x - 5 < 7
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1 year ago
Logan starts an IRA (Individual Retirement Account) at the age of 28 28 to save for retirement. He deposits $400 $ ⁢ 400 each mo
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Answer:

A) Total amount deposited over the length of investment = $177600

B) Interest accrued upon retirement = $1,043,678.01

Step-by-step explanation:

From the question, we can see that he started the savings at the age of 28 and ended when he retired at the age of 65. Thus, number of years = 65 - 28 = 37 years

We are told he deposited $400 each month and that upon retirement it had grown to $1,161,278.01.

Since he deposited $400 each month, in a year which has 12 months, he deposited;

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Now, it took 37 years before he retired which was the point at which he stopped the deposit.

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This means there was interest on the money.

Interest = $1,161,278.01 - $177600

Interest = $1,043,678.01

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