If I have a stack of pennies. And I have to tell that without counting whether there are even number of pennies or odd.
Even numbers are the numbers which are divisible by 2 and odd numbers are the numbers which are not divisible by 2.
Then I will put the given pennies in 2 rows and then I will match them to form a pair of 2 pennies.
After matching, if there is 1 penny left over, then there is an odd number of pennies and if all the pennies have a match,then there is an even number of pennies.
He made an error is step 2
3x + 18 = 2x +8
subtract 2x from each side
x + 18 = 8
Quantity of dolls and horses are 10 and 5 respectively .
Selling prices of dolls and horses are $7 and $ 9 respectively .
And the commission on them are $2 and $ 3 respectively .
So net price = 10*(7-2) + 5(9-3) = 10+5 + 5*6 = 50+30 = 80
So the total value of the merchandise using net realizable value is $ 80. Therefore out of the given options, correct option is the last option .
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
3x - 2y + 2 = 0 → -2y + 2 = -3x → -2y = -3x - 2 → y = 
x + 1
x - y + 3 = 0 → -y + 3 = -x → -y = -x - 3 → y = x + 3
These two equations have the same slope but different y-intercepts so they are parallel lines. (aka inconsistent).
Answer: Inconsistent, (0, 1), (0, 3)
