There are 2 red marbles and 3 blue marbles, with a total of 5 marbles in the bag.
When Jonathan chooses a marble, we are saying that he is choosing the marble randomly.
Let's make a fraction. We want to know the chance of picking one of the 2 red marbles among all 5 marbles.
Divide 2 by 5
2/5
That's already a simplified fraction. If you want to convert this into decimal and into percentage, you would get
2/5
= 0.4
= 40%
Those are all acceptable answers.
Have an awesome day! :)
Answer:
5 minutes
Step-by-step explanation:
9/6=40 mins per patient
8/6=45 mins per patient
"Then I will need an average quality score of <u>3.28</u> to meet 85.28 goal."
<u>Step-by-step explanation</u>:
- current average quality score = 82
- improvement on average quality score = 4% of 82
⇒ (4/100)
82
⇒ 82/25
⇒ 3.28
The improved average quality score = 82+3.28 = 85.28
The employee needs an average quality score of 3.28 to meet the goal of 85.28
Answer:
A + B + C = π ...... (1)
...........................................................................................................
L.H.S.
= ( cos A + cos B ) + cos C
= { 2 · cos[ ( A+B) / 2 ] · cos [ ( A-B) / 2 ] } + cos C
= { 2 · cos [ (π/2) - (C/2) ] · cos [ (A-B) / 2 ] } + cos C
= { 2 · sin( C/2 ) · cos [ (A-B) / 2 ] } + { 1 - 2 · sin² ( C/2 ) }
= 1 + 2 sin ( C/2 )· { cos [ (A -B) / 2 ] - sin ( C/2 ) }
= 1 + 2 sin ( C/2 )· { cos [ (A-B) / 2 ] - sin [ (π/2) - ( (A+B)/2 ) ] }
= 1 + 2 sin ( C/2 )· { cos [ (A-B) / 2 ] - cos [ (A+B)/ 2 ] }
= 1 + 2 sin ( C/2 )· 2 sin ( A/2 )· sin( B/2 ) ... ... ... (2)
= 1 + 4 sin(A/2) sin(B/2) sin(C/2)
= R.H.S. ............................. Q.E.D.
...........................................................................................................
In step (2), we used the Factorization formula
cos x - cos y = 2 sin [ (x+y)/2 ] · sin [ (y-x)/2 ]
Step-by-step explanation:
One centimenter is 0.01 meters. So, you can write the measures as
Once this rewriting is done, getting the total length 
is quite trivial, since all measurements are in the same unit, and we can simply sum everything:
