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2 years ago

8

Darrel just bought his very first mountain bike, an aluminum-framed front-and-rear suspension beauty that he's been saving for m

any months. For Darrel, the mountain bike is most likely what type of purchase?
A) minor repurchase
B) major new purchase
C) minor new purchase
D) major repurchase

2 answers:

ladessa [460]2 years ago

5 0

The answer is B. (hope that helps)

victus00 [196]2 years ago

4 0

Answer:

Major new purchase

Step-by-step explanation:

Apex

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The formula uppercase S = StartFraction n (a Subscript 1 Baseline plus a Subscript n Baseline) Over 2 EndFraction gives the part

yanalaym [24]

Answer:

Step-by-step explanation

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2 years ago

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Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 888 wings for \$7$7dollar

ella [17]

Cost of chicken wings at Buffalo Bills = 8 wings for $7

Cost of 1 wing at Buffalo Bills = $\frac{7}{8} =0.875$

Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10

Cost of 1 wing at Buffalo Mild Wings = $\frac{10}{12}= 0.833$

Cost of chicken wings at Wingers = 20 wings at $17

Cost of 1 wing at Wingers = $\frac{17}{20}= 0.850$

Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.

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2 years ago

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Lanie's Room Is In The Shape Of A Parallelogram. The Floor Of Her Room Is Shown And Has An Area Of 108 Square Feet. Lanie Has A

Fittoniya [83]

Answer:

The rug will fit on the floor of her room

Step-by-step explanation:

The floor's area is given as 108

Will the rug fit this area of 108 sq. ft.?? We have to find the area of the rug and if it is less than 108, then definitely it will fit.

The rug is in the shape of a rectangle. The area of a rectangle is length times width.

Given length 10 and width 6, the area is:

Area of Rectangle = 10 * 6 = 60

Area of Rug = 60

Is 60 less than 108?? Yes, definitely!

The rug will fit on the floor of her room

8 0

2 years ago

If m< LMP is 11 degrees more than m< NMP and m< NML =137, find each measure

Agata [3.3K]

First, note that for angles LMP and NMP you have

$m\angle LMP+m\angle NMP=m\angle NML.$

If $m\angle LMP$ is $11^{\circ}$ more than $m\angle MNP,$ then

$m\angle LMP=m\angle NMP+11^{\circ}.$

Now, since $m\angle MNL=137^{\circ},$ you have

$137^{\circ}=m\angle NMP+11^{\circ}+m\angle NMP,\\ \\2m\angle NMP=137^{\circ}-11^{\circ}=126^{\circ},\\ \\m\angle NMP=63^{\circ}.$

Therefore,

$m\angle LMP=63^{\circ}+11^{\circ}=74^{\circ}.$

Answer: $m\angle LMP=74^{\circ},\ m\angle NMP=63^{\circ}.$

7 0

2 years ago

Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box

Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

$z=\frac{1728}{xy}$

Surface area of box = $2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})$

Let $f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})$

To get minimal surface area

$\frac{\partial f}{\partial x}=0$ and $\frac{\partial f}{\partial y}=0$

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0$

$2y-2(\frac{1728}{x^2})=0$

$y=\frac{1728}{x^2}$ ----1

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0$

$2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2} \\y^2=\frac{1728}{x}$

Using 1

$(\frac{1728}{x^2} )^2=\frac{1728}{x}$

x=0 and $x^3=1728$

Side can never be 0

So, $x^3=1728$

x=12

$y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}$

y=12

$z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}$

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0

2 years ago