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Gnoma [55]
2 years ago
5

Marya plans to participate in a 20 km walk-a-thon. To prepare, she walked 4 km on Monday. She plans to increase her walk by 2 km

each week until she reaches 20 km.
Marya’s calculations:



The equation representing Marya’s calculations is . How many weeks will it take Marya to reach her goal of a 20 kilometer walk?
891012

Mathematics
2 answers:
SVEN [57.7K]2 years ago
5 0

Answer:

the answer is 8

Step-by-step explanation:

dybincka [34]2 years ago
3 0
It would take 8 weeks
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A thin sheet of ice is in the form of a circle. If the ice is melting in such a way that the area of the sheet is decreasing at
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Answer:

dx/dt  =  0,04 m/sec

Step-by-step explanation:

Area of the circle is:

A(c) =π*x²      where   x is a radius of the circle

Applying differentiation in relation to time we get:

dA(c)/dt   =  π*2*x* dx/dt    

In this equation we know:

dA(c)/dt  = 0,5 m²/sec

And are looking for dx/dt then

0,5  = 2*π*x*dx/dt    when the area of the sheet is 12 m²  (1)

When  A(c) = 12 m²      x = ??

A(c)  =  12  =  π*x²      ⇒    12  =  3.14* x²    ⇒  12/3.14  =  x²

x²  = 3,82     ⇒   x  = √3,82    ⇒  x = 1,954 m

Finally plugging ths value in equation (1)

0,5  = 6,28*1,954*dx/dt

dx/dt  =  0,5 /12.28

dx/dt  =  0,04 m/sec

7 0
1 year ago
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A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t
maksim [4K]

Answer:

Boat traveled 553.24 feet towards the lighthouse.

Step-by-step explanation:

In the figure attached AB is the light house of height 200 feet.

Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'

so 1' = \frac{1}{60} degree

so angle of elevation at point C = 14 + \frac{52}{60}

So angle of elevation from C = (14 + 0.87) = 14.87°

Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + \frac{10}{60} = 45.17°

Now we have to calculate the distance CD, traveled by the boat.

In ΔABC

tan14.87 = \frac{200}{BC}

0.2655 =  \frac{200}{BC}

BC = \frac{200}{0.26552}

BC = 753.239 feet

Similarly in ΔABD

tan45.17 = \frac{200}{BD}

1 = \frac{200}{BD}

BD = 200 feet

So distance CD = BC - BD

CD = 753.239 - 200

     = 553.24 feet

Therefore, Boat traveled 553.24 feet towards the lighthouse.

7 0
2 years ago
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Sal was tired of waiting for Amir to show up at their meeting place, so he started running at an average speed of 4.5 mph withou
skelet666 [1.2K]
Let s and a represent the position of Sal and Amir respectively.

s=.75+4.5t  and a=-.25+6.7t

When Sal catches Amir, s=a so we can say.

-.25+6.7t=.75+4.5t  subtract 4.5t from both sides

-.25+2.2t=.75  add .25 to both sides

2.2t=1  divide both sides by 2.2

t=5/11 hours

t≈0.45 hours  (to nearest hundredth of an hour)
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2 years ago
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Segmented animals without a backbone are called?
puteri [66]
They are called invertebrats
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2 years ago
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Tesla wanted to determine the average miles per kWh that their vehicles get across all models and variations. They took a sample
LiRa [457]

Answer:

\mu_{\bar x} = \mu = E(X) =30KWh

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we select a sample of n =100

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

So then the sample mean would be:

\mu_{\bar x} = \mu = E(X) =30KWh

And the standard deviation would be:

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

6 0
1 year ago
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