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Sergio039 [100]
1 year ago
6

8 students share 5 square pieces of cake equally

Mathematics
2 answers:
k0ka [10]1 year ago
6 0
You divide the numbers to get your answer
Alla [95]1 year ago
3 0
Each student has 8/5 or 1.6 of the cake
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After dinner 2/3 of the corn bread is left suppose 4 friends want to share it equally. What fraction names how much of whole pan
Bogdan [553]
Each person would get 1/6 of the pan of corn bread that was left.  2/3 divided by 4= 1/6
3 0
1 year ago
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Using the exchange rate £1 = $1.33, calculate how many £ are in $6.50. Give your answer rounded to 2 dp.
juin [17]

Answer:

Step-by-step explanation:

If the exchange rate between British pounds (£) and US dollars ($) is £1 = $1.40, how much is £200 worth in dollars?

Include the $ sign in your answer.

280

$142.86

280.00

$280.00

$280

42.86

6 0
1 year ago
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Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x? StartRoot 1 plus-or-minus StartRoot 159 En
castortr0y [4]

For this case we have that a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

We have the following equation:

4x ^ 2-3x + 9 = 2x + 1\\4x ^ 2-3x-2x + 9-1 = 0\\4x ^ 2-5x + 8 = 0

We look for the roots:

x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (4) (8)}} {2 (4)}\\x = \frac {5 \pm \sqrt {25-128}} {8}\\x = \frac {5 \pm \sqrt {-103}} {8}

We have to:

i ^ 2 = -1

So:

x = \frac {5 \pm \sqrt {103i ^ 2}} {8}\\x = \frac {5 \pm i \sqrt {103}} {8}

We have two imaginary roots:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

Answer:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

8 0
2 years ago
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Write a sentence for this equation 2n+1=6n
Usimov [2.4K]

Answer:

875246b438b f34 43

Step-by-step explanation:

4 0
2 years ago
Which expressions are equivalent to StartFraction 1 Over 36 EndFraction? Check all that apply. 3 Superscript negative 6 6 Supers
Elenna [48]

Answer:

6^-2

6^3/6^5

6^-9 *6^ 7

Step-by-step explanation:

We want the fractions equal to 1/36

We know that a^-b = 1/a^b

We also know that a^b / a^c = a^(b-c)

We also know that a^b * a^c = a^(b+c)

3^ -6 = 1/3^6 = 1/729

6^-2 = 1/6^2 = 1/36

6^3/6^5 = 6^(3-5) = 6^-2 = 1/6^2 = 1/36

6^2 / 6^-1 = 6^(2- -1) = 6^3 = 216

6*6^-2 = 6^(1-2) = 6^-1 = 1/6

6^-9 *6^ 7 = 6^(-9+7) = 6^ -2 = 1/6^2 = 1/36

5 0
1 year ago
Read 2 more answers
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