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2 years ago

7

A coach gives her players the option of running around their field twice or around their entire stadium once. The following diag

ram shows the field and stadium dimensions on a coordinate grid.

1 answer:

Elodia [21]2 years ago

7 0

Get a call to me when I can do it on Saturday

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Danika concludes that the following functions are inverses of each other because f(g(x)) = x. Do you agree with Danika? Explain

nordsb [41]

I hope this helps you..;

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2 years ago

Read 2 more answers

The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin

Free_Kalibri [48]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.03

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03$

$=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12$

Thus, 8.17 g separates the top 3% of the weights.

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90$

Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

7 0

2 years ago

In a sale normal prices are reduced by 10% Nathalie bought pair of shoes in the sale for ?54 what was the original price

Mama L [17]

Answer:

$59.4

Step-by-step explanation:

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2 years ago

People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the

Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

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2 years ago

a hatchling turtle has a shell with a 1-inch diameter. the shell keeps a similar shape as the turtle grows. compare the volume a

earnstyle [38]

Answer would be 4 multiple

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2 years ago