Answer:
Having 2 meters and 25 meters legs and 3 meters and 30 meters legs.
Step-by-step explanation:
Priya thinks that an angle of elevation of 7 Degrees or less will be safe for a learner of bike riding.
Now, a 7-degree elevation angle in a right triangle will have a 3 : 25 ratio of its legs.
Therefore, the list of 2 right triangles that would be safe for a new rider will be having 2 meters and 25 meters legs and 3 meters and 30 meters legs.
I both cases the angle of elevation will be less than 7 degrees. (Answer)
Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}
Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid
For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36
Total amount to be paid in 20 years, A1 = 376.36*20*12 = $90,326.30
For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22
Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98
The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32
Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.
C..The median of Nadia’s data is equal to the median of Ben’s data. D. Nadia had the highest score on a test......?.......?
Answer: $600,600
Step-by-step explanation:
Total handling cost :
Workpiece moved * cost * distance
Work area A :
-, (5 × 22 × 900), (9 × 22 × 900), (7 × 22 × 500)
-, 99000, 178200, 77000
Work area B:
-, -, (6 × 22 × 500), (8 × 22 × 200)
-, -, 66000, 35200
Work area C:
-, -, -, (11 × 22 × 600)
-,-,-, 145200
Work area D:
-, -, -, -
Total weekly handling cost :
(99000 + 178200 + 77000 + 66000 + 35200 + 145200)
= $600,600
Kindly check attached picture for more explanation
Answer:
35.7 km and 248.3 °
Step-by-step explanation:
I will attach the diagram to an image to make it easier to understand.
We will use the formula corresponding to the law of cosine
y² = 42² + 28² - (2 * 42 * 25 * cos 58 °)
y² = 2389 - 1112.83 = 1276.17
y = √1276.17
y = 35.72 km
Now, to calculate the surveyor's bearing from her base camp we must use the sine law:
[(Sin 58 °) / y] = [(Sin A) / 42]
Without A = (42 * without 58 °) /35.72
A = sin⁻¹ (0.9971)
A = 85.7 °
Bearing of the surveyor from the base camp = 270 ° - (85.7 ° - 64 °) = 248.3 °
