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Inessa05 [86]
2 years ago
12

Julian has to read 4 articles for school. He has 8 nights to read them. He decides to read the same number of articles each nigh

t.
a. How many articles will he have to read per night?
b. What fraction of the reading assignment will he read each night?
Mathematics
1 answer:
daser333 [38]2 years ago
5 0

<u><em>Answer:</em></u>

a. He will have to read half an article per night

b. Fraction of the reading assignment read each night = \frac{0.5}{4}=\frac{1}{8}

<u><em>Explanation:</em></u>

<u>Part a:</u>

<u>We are given that:</u>

number of articles to read = 4 articles

number of nights = 8 nights

To get the number of articles that he should read per night, we will simply divide the the number of articles by the number of nights

<u>Therefore:</u>

number of articles to read per night = \frac{4}{8}=\frac{1}{2} articles per night

<u>Part b:</u>

Now, we know that he will read half an article each night from a total of 4 articles

To get the fraction of the reading assignment read each night, we will divide the number of articles read each night by the total number of assignments

<u>Therefore:</u>

Fraction of the reading assignment read each night = \frac{0.5}{4}=\frac{1}{8}

Hope this helps :)

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The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The
ziro4ka [17]

<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

<em>Sal’s mother would have to keep the second cell phone plan for at least months in order for it to be less expensive.</em>

Answer:

a. 150 + 51x < 100 + 55x

b. x > 12.5

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

Solving (b): Inequality Solution

150 + 51x < 100 + 55x

Collect Like Terms

51x-55x

-4x

Solve for x

x > -50/-4

x > 12.5

Solving (c): Interpret the solution in (b)

x > 12.5 implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

4 0
2 years ago
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lianna [129]
For this case, what you should know is that Sue Jones insurance covers half of the expenses. Equivalently, her insurance covers:
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 b. for Sam 
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 answer
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 $ 4000
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ruslelena [56]
X*80+y*60= 50*74
x      +y      =50            | * ( -60)

80x  + 60y= 50*74
-60x  - 60y=-50*60
---------------------------
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2 years ago
Which of the following groups has terms that can be used interchangeably with the others?1. Percentage, Probability, and Proport
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Answer: 1) Percentage, Probability, Proportion

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In statistics,

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balu736 [363]

Answer:

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Part A

Basic Formula

c = k/d

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Part B

c = 68

k = 34

d = ?

68 = 34/d               Multiply both sides by d

68*d = 34 * d/d      Simplify.

68 d = 34                Divide by 68

d = 34/68                Simplify

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