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Aleks [24]
2 years ago
10

Write the expression n.n.p.p.r.r.r

Mathematics
1 answer:
borishaifa [10]2 years ago
7 0

Answer:

2n.2p.3r

Step-by-step explanation:

idk

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You are given the sequence of digits 0625 and can insert a decimal point at the beginning at the end or at any of the other thre
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Answer:

The answer is 6/25.

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Harper knows he is 50 yards from school. The map on his phone shows that the school is 34 inch from his current location. How fa
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To solve this problem you must apply the proccedure shown below:

1. We know that 1 yard is 36 inches, therefore, 50 yards expressed in inches is:

(50)(36)=1800in

2. If he is 50 yards from school and the map shows that the school is 34 inches from his current location, when it shows 3 inches the real distance is:

\frac{(1800in)(3in)}{34in}=158.82in

3. If you can to express it in yards:

\frac{158.82}{36} =4.41 yd

Therefore, the answer is: 158.82 inches or 4.41 yards.

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Jerry is a judge he hears 5 cases every 2 3/8 per hours Jerry hears case at a constant rate How many cases does he hear per hour
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Around 2 I think... 2.10 is what I got 
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2 years ago
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A group of 55 football players were polled about which synthetic grass they like to play on, Chemstrand or Chemgrass. The data f
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From the Venn diagram: 15 players like Chemstrand, 17 players like Chemgrass, 13 players like both Chemstrand and Chemgrass while 10 players like neither Chemstrand nor Chemgrass.

The missing values in the frequency table are x - representing the number of players that like both Chemstrand and Chemgrass, y - representing the number of players that like Chemgrass but do not like Chemstrand and z - representing the number of players likes Chemstrand but do not like Chemgrass.

The number of players that like both Chemstrand and Chemgrass is 13. The number of players that like Chemgrass but do not like Chemstrand is 17. The number of players likes Chemstrand but do not like Chemgrass is 15.

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2 years ago
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You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal
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Answer:

Probability each player gets an ace, a $2 and a $3 = 0.0374

Step-by-step explanation:

The total number of ways to divide the card in triples among four players = 369600 ways

The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways

Probability each player gets an ace, a $2 and a $3 = 13824/369600

Probability each player gets an ace a $2 and a $3 = 0.0374

Note: Further explanation is provided in the attachment.

8 0
2 years ago
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