On one afternoon in a shoe warehouse, three large shipments of shoes arrived. The weights of the shipments were 1 ton 115 pounds
1 answer:
Alright, lets get started.
The weight of first shipment = 1 ton 115 pounds
As we know, 1 ton = 2000 pounds, so
So, the weight of first shipment = pounds
The weight of second shipment = 1723 pounds 7 ounces
The weight of third shipment = 957 pounds 11 ounces
So, adding all three weights =
So, all three weights = 4795 pounds 18 ounces
As we know, 16 ounces = 1 pound, so
all three weights = 4795 pound 1 pound 2 ounces
All three weights = 4796 pounds 2 ounces
4796 could be wriiten as 4000 + 796
As we know, 2000 pound = 1 ton so
All three weight = 2 tons 796 pounds 2 ounces
So, the total weight of three shipments = 2 tons 796 pounds 2 ounces : Answer
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Answer:
And when we apply the limit we got that:
Step-by-step explanation:
Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"
We have the following formula in order to find the sum of cubes:
We can express this formula like this:
And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2
If we operate and we take out the 1/4 as a factor we got this:
We can cancel and we got
We can reorder the terms like this:
We can do some algebra and we got:
We can solve the square and we got:
And when we apply the limit we got that: