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den301095 [7]
2 years ago
14

The following random sample from a population whose values were normally distributed was collected.10 8 11 11The 95% confidence

interval for μ is:a. 8.00 to 10.00b. 7.75 to 12.25c. 9.75 to 10.75d. 8.52 to 10.98
Mathematics
1 answer:
Margaret [11]2 years ago
6 0

Answer:

Answer:

B

Step-by-step explanation:

First to find the sample mean

Xbar= summation x/n= 40/4= 10

The sample standard deviation is:

S= √summation(x-xbar)²/ n-1

=√6/3= 1.4142

The degrees of freedom

df= N-1= 4-1= 3

For 95% confidence level, critical value of t

t= 3.182

The 95% confidence interval is:

=Xbar plus or minus t' *8/√n

= 10 plus or minus 3.182(1.4142/√4)

= 10plus or minus 2.25

So 7.75 or 12.25

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A dollar store sells items for $1 and $2. You plan to go there and spend at least $20. Let x stand for the number of one-dollar
Eduardwww [97]

Answer:

x * 10 + y *5

Step-by-step explanation:

8 0
2 years ago
9 days ago the area covered by a mold and a piece of bread with three square inches today the mold covers 9 square inches find t
Kazeer [188]

9 days ago, the mold covered an area of 3in^{2}.

Today (after 9 days), the mold covers an area of 9in^{2}.

<em>What is the increase in area?</em> It went from 3 to 9. So the increase is 9-3=6 in^{2}.

Now, we need to find <em>rate of change</em>. It means to find  how much the area increased every day over the past 9 days. We simply divide <em>the increase (6)</em> by the <em>total number of days (9)</em> to find the rate per day. So we have,

\frac{6}{9} =\frac{2}{3}  in^{2}

ANSWER: Change of Rate = \frac{2}{3} in^{2} per day

6 0
2 years ago
Read 2 more answers
Biologists stocked a lake with 240 fish and estimated the carrying capacity (the maximal population for the fish of that species
LUCKY_DIMON [66]

Answer:

2.30 years

Step-by-step explanation:

The number of fish tripled in the first year, making a total of 240 * 3 = 720 fishes.

(a) The formula for logistic equation is as the following

P = P_0e^{kt}

where P0 = 240 is the number of fishes initially, we can plug in P = 720 and t = 1 to calculate the constant k

720 = 240e^{1k}

e^k = 3

k = ln3 = 1.1

b) Using the following formula

P = P_0e^{kt}

with P = 3000, P0 = 240, k = 1.1, we can calculate the number of years it takes to get to 3000 fishes

3000 = 240e^{1.1t}

12.5 = e^{1.1t}

1.1t = ln12.5 = 2.53

t = 2.30 years

6 0
2 years ago
A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting
sammy [17]

Answer:

The overview of the given problem is outlined in the following segment on the explanation.

Step-by-step explanation:

The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:

Checking a probability of transmitting becomes "p".

After considering two or even more attempts, we get

Slot fraction wasted,

= [1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]

On putting the values, we get

= 1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]

= 1-(1-P)^{N}-N[P(1-P)^{N}]

So that the above seems to be the right answer.

8 0
2 years ago
Which statement best describes the use of a simulation to predict the probability that two randomly chosen people will both have
laila [671]
<span>Randomly generate an integer from 1 to 7 two times, and the probability is 1/7 ^2

This is the </span><span>statement that best describes the use of a simulation to predict the probability that two randomly chosen people will both have their birthdays on a Monday.

There are 7 days in a week, so there are 7 choices but only 1 Monday. So, 1/7 is the probability that a person's birthday falls on a Monday.

1st person asked will have 1/7 probability.
2nd person asked will also have 1/7 probability

So, (1/7)</span>² is the probability that both persons will have their birthdays on a Monday.
8 0
2 years ago
Read 2 more answers
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