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Deffense [45]
1 year ago
13

197 people ride the bus in the morning. 10 less than 84 people ride the bus in the evening. How many people ride the bus in all?

Mathematics
1 answer:
SVETLANKA909090 [29]1 year ago
7 0

Answer:

Step-by-step explanation:

128

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What error did Maria likely make?
raketka [301]
She didn’t notice that the 3 and the 4 both do not have the variable “n” with them
She just added up all the numbers together then added the variable at the end.
7 0
2 years ago
Suppose that a high school marching band has 125 members. Of these 125 band members, 41 are seniors, 24 play the trumpet, and 10
Alborosie

Answer:

<em>The probability is 42%</em>

Step-by-step explanation:

<u>Conditional Probability</u>

It's the probability of the occurrence of an event B knowing that an event A has already occurred and A and B are related (not independent).

If P(A) is the probability of occurrence of A, P(A\cap B) is the probability of both events to occur, and P(B|A) is the required probability occurrence of B:

\displaystyle P(B|A)=\frac{P(A\cap B)}{P(A)}

We know a high school marching band has 125 members, from which 41 are seniors (event B), 24 play the trumpet (event A), and 10 are seniors who play the trumpet.

The probability that a randomly selected band member plays the trumpet is

\displaystyle P(A)=\frac{24}{125}

The probability that he or she has both attributes is

\displaystyle P(A\cap B)=\frac{10}{125}

Thus, the required conditional probability is

\displaystyle P(B|A)=\frac{\frac{10}{125}}{\frac{24}{125}}

\displaystyle P(B|A)=\frac{10}{24}=\frac{5}{12}=0.42

The probability is 42%

5 0
2 years ago
M∠AFD=90°. m∠AFB=31°. Find m∠CFEm.
Setler [38]
AFB = CFD = 31
BFC = 90 - (31+31) = 28
DFE = BFC = 28
CFE = CFD + DFE = 31 + 28 = 59
7 0
1 year ago
Read 2 more answers
Select all the pairs that could be reasonable approximations for the diameter and circumference of a cirlce 5 meters and 22 mete
bazaltina [42]

Answer:

Option a) circle 5 meters and 22 meters

Step-by-step explanation:

We are given the following information in the question:

A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.

a) circle 5 meters and 22 meters

\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}

b) 19 inches and 50 inches

\text{Diameter} = 19\text{ inches}\\\text{Circumference} = \pi d = 3.14\times 19 = 59.66\text{ inches}

c) 33 centimeters and 80 centimeters

\text{Diameter} = 33\text{ centimeters}\\\text{Circumference} = \pi d = 3.14\times 33 =103.62\text{ centimeters}

Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.

6 0
2 years ago
Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. The results in the screen disp
e-lub [12.9K]

Answer:

D. is the correct answer, hope this helps!


4 0
1 year ago
Read 2 more answers
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