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2 years ago

14

What are the solutions of 8x2 = 6 + 22x? Check all of the boxes that apply.

2 answers:

Sholpan [36]2 years ago

6 0

Transpose all the terms in the left hand side of the equation. The equation then becomes,
8x² - 22x - 6 =0
Divide both sides of the equation by 2,
4x² - 11x - 3 = 0

In this equation, A = 4, B = -11, and C = -3

With the variables identified, the quadratic equation can be used to identify the roots,
x = (-B +/- √B² - 4AC) / 2A
The values of x in the equation are,
<em> x = 3 and x = -1/4
</em><em />Thus, the one of the answer to this item is the third choice, x = 3. <em>
</em>

bogdanovich [222]2 years ago

6 0

Answer:

b and c

Step-by-step explanation:

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The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c

Slav-nsk [51]

$\text{Answer} : \text{The expected value of a t-shirt is \$31.}$

Explanation:

Since we have given that

The prices of three t-shirts styles i.e $24, $30, $36 with their probability is given by

$\frac{1}{6}, \frac{1}{2},\frac{1}{3}$

As we know that,

$E(X)= \sum_{1}^{3}x_iP(x_i)$

$\text{where} x_i \text{ is the prices of t- shirts styles}$

Now,

$x_1= \$24 , x_2=\$30 , x_3=$36$

and

$P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}$

So,

$E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31$

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2 years ago

Josiah takes a multiple-choice quiz that has three questions. Each question has five answer options. If he randomly chooses his

ahrayia [7]

The answer is 1/125.

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A sausage company makes two different kinds of hot dogs, regular and all-beef. Each pound of all-beef hot dogs requires 0.75 lb

Gre4nikov [31]

Answer:

880 lbs of all-beef hot dogs
2000 lbs of regular hot dogs
maximum profit is $3320

Step-by-step explanation:

We can let x and y represent the number of pounds of all-beef and regular hot dogs produced, respectively. Then the problem constraints are ...

.75x + 0.18y ≤ 1020 . . . . . . limit on beef supply
.30y ≤ 600 . . . . . . . . . . . . . limit on pork supply
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And the objective is to maximize

p = 1.50x + 1.00y

The graph shows the constraints, and that the profit is maximized at the point (x, y) = (880, 2000).

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The width of a triangle is six more than twice the height. The area of the triangle is 88in2. Find the height and base of the tr

malfutka [58]

For this case we have that by definition, the area of a triangle is given by:

$A = \frac {b * h} {2}$

Where:

b: It is the base of the triangle

h: It is the height of the triangle

According to the statement data we have:

$b = 6 + 2h$

Substituting we have:

$88 = \frac {(6 + 2h) * h} {2}\\176 = 6h + 2h ^ 2\\2h ^ 2 + 6h-176 = 0$

We divide between 2 on both sides:

$h ^ 2 + 3h-88 = 0$

We factor by looking for two numbers that, when multiplied, are obtained -88 and when added together, +3 is obtained.

These numbers are +11 and -8.

$(h + 11) (h-8) = 0$

We have two roots:

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We choose the positive value.

Thus, the base of the triangle is: $b = 6 + 2 (8) = 22$

Answer:

The base of the triangle is 22 units.

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Answer:

Step-by-step explanation:

solution attached below

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