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Kobotan [32]
1 year ago
15

A gardener wants to plant 122500 trees in his field in such a way that the number of trees in a row is equal to the number of ro

ws .How many trees will he plant in each row?
Mathematics
1 answer:
Nady [450]1 year ago
6 0
Given that the gardener wants the number of trees in each raw to be equal to the number of rows, then let the number of in each row be x this means that the number of rows will be x.
Thus the total number of trees will be:
Total=(number of rows)*(number of trees in each row)
hence:
122500=x×x
122500=x²
hence
x=√122500
x=350
thus the number of rows will be 350 and the number of trees in each row will be 350
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Show one way to count from $82 to $512
Sedaia [141]
<span><u><em>First way:</em></u>
The easiest and simplest way is to <u>count by 1</u> starting from 82 till you reach 512.
<u>This will go as follows:</u>
82, 83, 84, 85, ........... , 510, 511, 512

<u><em>Second way:</em></u>
We can note that the two given numbers are even numbers. This means that the two numbers are divisible by 2.
Therefore, we can <u>count by 2</u> starting from 82 till we reach 512.
<u>This will go as follows:</u>
82, 84, 86, 88, ................... , 508, 510, 512

<u><em>Third way:</em></u>
We can note that the units digit in both numbers is the same (the digit is 2). This means that we can count from 82 till 512 by <u>adding 10 each time</u>.
<u>This will go as follows:</u>
82, 92, 102, 112, ......................, 492, 502, 512

Hope this helps :)</span>
5 0
1 year ago
Please answer all of them need this
VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

Since, Sin(75^0)=\frac{CQ}{8}

\therefore CQ=8\times Sin(75^0)\approx 7.73 ft

In a similar manner we can find BQ as:

Cos(75^0)=\frac{BQ}{8}

BQ\approx2.07 ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

PQ=22-(AP+QB)=22-(2.07+2.07)=17.86

Let us now consider\Delta AQC

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of \Delta AQC.

AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38 feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area=\frac{1}{2}(First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area=\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845 m^2

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}

This gives a to be:

a\approx28.44

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





8 0
2 years ago
Read 2 more answers
In triangle $DEF,$ $\angle D = 30^\circ,$ $\angle F = 60^\circ,$ and $EF = 6.$ Find $DE + DF.$ [asy] unitsize(2 cm); pair D, E,
sergey [27]

Answer:

Step-by-step explanation:

The answer to this question is 12+6sqrt3.

This is because of the 30, 60, and 90 degree rule. The rule states that the hypotenuse is equal to twice the length of the shorter leg, which is the side across from the 30 degree angle.

Using the rule you now know that DF is 12. Then use the Pythagorean Theorem to find the length of DE. 12^2=144, and 6^2=36. 144-36=108.

The square root of 108 simplified=6sqrt3.

Then you add them together and get 12+6sqrt3.

5 0
2 years ago
39x5 in distributive property
alexira [117]
 the answer is
30 x 5 + 9 x 5
7 0
2 years ago
For every $10 Glen earns, his parents
irga5000 [103]

10-2 = 8

He can spend $8

$8/$10 = 0.80

0.80 x 100 = 80 %

He can spend 80%

8 0
1 year ago
Read 2 more answers
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