Answer:
If both Kelsey and Jeana purchase 6 pairs of uniform pants then they would pay the same amount for their purchases.
Step-by-step explanation:
The information provided is as follows:
- Kelsey buys several pairs of uniform pants for $17.95 each, and a sweater for $24.
- Jeana shops at a different store and buys several pairs of uniform pants for $18.95 each, plus a sweater for $18.
The variable <em>x</em> is the number of pairs of pants.
The total cost function for Kelsey will be:
The total cost function for Jeana will be:
Consider that both pay the same total cost for their purchases.
Compute the value of <em>x</em> as follows:
Thus, if both Kelsey and Jeana purchase 6 pairs of uniform pants then they would pay the same amount for their purchases.
Break even point is where all the expense is already covered by the revenue. In this case, the expense would be the stand ($75,000) and the lemon+sugar+water ( $1.25 per glass). The revenue comes from lemonade($30/glass). Then the equation would be:
$30 * glass of lemonade= $75,000 + $1.25 * glass of lemonade
($30-$1.25) * glass of lemonade= $75,000
glass of lemonade= 2608.7
Then, 15 - x is the distance ran in the second part.
The time, t1, for the first part is t1 = xmi / 8mi/h
The time, t2, for the second part is t2 = (15 - x)mi / 20mi/h
The total time is t1 + t2 = 1.125 h
Then x/8 + (15 - x) / 20 = 1.125
To solve for x, multiply both sides by 40 (this is the least common multiple)
5x + 30 - 2x = 45
3x = 15
to find x divide: 15/3=5
And 15 - x = 10 mi.
First part:
Speed: 8mi/h
Distance: 5 mi
Time: 5mi/8mi/h = 5/8 h = 37.5 minutes
Second part
Speed: 20 mi/h
Distance: 10 mi
Average speed: 15mi/1.125h =13.33 mi/h
Distance: 15mi
Time: 1.125 h = 67.5 minutes
You need to solve for one variable in equation 1 and substitute it in equation 2 to solve.
Equation 1: x+y=24
x= number of 3 pt questions
y= number of 5 pt questions
24= Total number of questions
Equation 2: 3x+5y=100
100= Total point value possible on test
3x= point value of 3 pt questions
5y= point value of 5 pt questions
x+y=24
Subtract y from both sides
x=24-y
Substitute in equation 2:
3x+5y=100
3(24-y) +5y=100
72-3y+5y=100
72+2y=100
Subtract 72 from both sides
2y=28
Divide both sides by 2
y=14
Substitute y=14 back in to solve for x:
3x+5y=100
3x+5(14)=100
3x+70=100
Subtract 70 from both sides
3x=30
Divide both sides by 3
x=10
So there are 10 three point questions
There are 14 five point questions.
Hope this helped! :)
Answer:-8x^2-6x+36xy^2+27y^2
Step-by-step explanation:
using the FOIL method
