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Scrat [10]
2 years ago
7

A model that describes the population of a fishery in which harvesting takes place at a constant rate is given by dP dt = kP − h

, where k and h are positive constants. (a) Solve the DE subject to P(0) = P0. P(t) = (b) Describe the behavior of the population P(t) for increasing time in the three cases P0 > h/k, P0 = h/k, and 0 < P0 < h/k. P0 > h/k P(t) decreases as t increases P(t) increases as t increases P(t) = 0 for every t P(t) = P0 for every t P0 = h/k P(t) decreases as t increases P(t) increases as t increases P(t) = 0 for every t P(t) = P0 for every t 0 < P0 < h/k P(t) decreases as t increases P(t) increases as t increases P(t) = 0 for every t P(t) = P0 for every t (c) Use the results from part (b) to determine whether the fish population will ever go extinct in finite time, that is, whether there exists a time T > 0 such that P(T) = 0. If the population goes extinct, then find T. (If the population does not go extinct, enter DNE.)
Mathematics
1 answer:
Vadim26 [7]2 years ago
8 0
It increases at T because the behavior increased its speed
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89

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There are only 30 pages but last page number is 89.

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The ratio of losses to wins for Kyle's team is 3 to 2. If the team had played the same number of games, but had won twice as man
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Answer: The new ratio will be 1/4

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So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4

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NikAS [45]
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I believe it’s the 3rd one.

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Xelga [282]

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